eiffel - Thanks very much - that's very useful

Very clear and readable answer that´s strictly oriented to what has
been asked. - That´s the way I like it !

amazing...i'm very impressed by the thorough, detailed, and well-cited answer

Super answer! It was one of those things that was just driving me
crazy not being able to track down. I had mentioned this to a friend
in the lab, and they -understandably- didn't believe it.

Thanks!

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Excellent, eiffel!  A positive ID, without a doubt.  Thank you very much.

Apteryx

The answer I received was given to me in a timely manner, and I found
it very useful in my research of William Caslon.

This was definately worth the tip I gave.  Unfortunately I'm not a
cash rich person, so couldn't tip much.  However in a karmic sense,
this researcher is clearly already rich beyond most peoples dreams!

Many thanks, just what I wanted; you're a credit to Google Answers.

For the record, we decided on the plumbed Contessa machine for £265.

Regards,

A

Thank you very much, this is what I was expecting. Excellent answer.

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perfect, thanks.

No need to apologise, Eiffel, you deserve a reward for your magnificent efforts.

Please tell the Editors that your Answer is great

Warmest Regards

Bryan

Thanks a lot. I am delighted to have found this amazing Google service.

This was excellent and answered my question. This was really the best
reasonable response time.

Thanks!!!  Quite helpful.  I guess there is no perfect answer since
this depends on the LEDs I use, but knowing that I'm probably not
losing anything close to 7/8ths of the percieved brightness (and might
even be gaining some) is good enough.  Thanks!

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Thank you.
The answer provided was presented very professional, I got just the
information that I have requested, and more. eiffel-ga is great :)

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I asked a simple question and received an extensive answer...way to go :)

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Thanks for all your effort in answering my question.  Although the
title of my film looks like being very difficult to pin down, we have
at least discovered the theme and lots of pointers as to what it
possibly was.  I am impressed with the research conducted and will be
sure to use this service again.

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Bingo! Thanks so much for the help.

Solid advice, supported with facts. Very responsive. Thanks eiffel-ga.

That's great - thanks very much. Although I use a Mozilla based
browser I was unaware of its own capabilities in this area which are
even better than the web based options. Thanks again.

Hi eiffel-ga,

Thanks for your reply, it has helped me bringing my code up and
running.  I just turned the "Read *" statement into a readline()
method in Java using the BufferReader object, so taking in user
inputs, as you will see from the source code below.  Thanks again
eiffel-ga.

import java.lang.*;
import java.text.*;
import java.io.*;

public class explpa
{
   public static void main (String[] args) throws IOException
   {
      double U[] = new double [500];
      double V[] = new double [500];
      double dT, dx, THALF;
      int NP1, I, stdio;
      double T = 0.0;

      final double Tf = 20.0;
      final double Len = 10.0;
      final int N = 10;
      final double K = 0.53;
      final double C = 0.226;
      final double Rho = 2.70;
      final double Ratio = 0.25;
      
      NumberFormat dfmt = NumberFormat.getNumberInstance ();
      dfmt.setMaximumFractionDigits(3);
      dfmt.setMinimumFractionDigits(3);
      dfmt.setGroupingUsed(false);
      InputStreamReader isr = new InputStreamReader (System.in);
      BufferedReader br = new BufferedReader (isr);

      stdio = Integer.parseInt (br.readLine());
      NP1 = N +1;
      dx = Len / N;
      dT = ( Ratio * C * Rho * dx * dx ) / K;
      for (I = 1; I <= NP1; I++)
              U[I] = stdio;
      Output1(T,Len,dx,T,U, NP1);
      
      do
      {
        THALF = T + dT / 2.0;
        U[1] = Left();
        U[N + 1] = Right();
        for (I = 2; I <= N; I++)
        {
           V[I] = Ratio * (U[I + 1] + U[I - 1]) + (1.0 - 2 * Ratio) *
U[I];
        }
        T = T + dT;
        V[1] = Left();
        V[NP1] = Right();
        Output2(T, V, NP1);

        if (T > Tf) break;	//not a very good programming technique,
but will do for now

        THALF = T + dT / 2.0;
        V[1] = Left();
        V[N + 1] = Right();
      
        for (I = 2; I <= N; I++)
        {
           U[I] = Ratio * (V[I + 1] + V[I - 1]) + (1.0 - 2 * Ratio) *
V[I];
        }

        T = T + dT;
        U[1] = Left();
        U[NP1] = Right();
        Output2(T, U, NP1);

        if (T > Tf) break;	//not a very good programming technique,
but will do for now

      }
      while (true);	//not a very good programming technique, but will
do for now

   }

   static void Output1 (double x_from, double x_to, double delta_x,
double at_T, double U[], int NP1)
   {
      NumberFormat dfmt = NumberFormat.getNumberInstance();

      dfmt.setMaximumFractionDigits(3);
      dfmt.setMinimumFractionDigits(3);
      dfmt.setGroupingUsed(false);

      StringBuffer OutputMessage = new StringBuffer();
         OutputMessage.append("Potential values in one dimension by
explicit method\n");
         OutputMessage.append ("   For X =   ");
         OutputMessage.append ( x_from );
         OutputMessage.append (" to X =   ");
         OutputMessage.append ( x_to );
         OutputMessage.append (" with delta X of   ");
         OutputMessage.append ( delta_x );
         OutputMessage.append ("\n\n");
         OutputMessage.append ("At T =  ");
         OutputMessage.append ( dfmt.format(at_T) );

      System.out.println(OutputMessage.toString());

      int k=0;

      for (int i = 1; i <= NP1; i++)
      {
         System.out.print("  " + dfmt.format(U[i]));

         k++;

         if (k==6) System.out.println();
      }

      System.out.println();
      System.out.println();

   }

   static void Output2 (double T, double V[], int NP1)
   {
      NumberFormat dfmt = NumberFormat.getNumberInstance();
      dfmt.setMaximumFractionDigits(3);
      dfmt.setMinimumFractionDigits(3);
      dfmt.setGroupingUsed(false);
      
      System.out.print("Values at T = " + dfmt.format(T) + "\n");

      int k=0;

      for (int i = 1; i <= NP1; i++)
      {
         System.out.print("  " + dfmt.format(V[i]) );

         k++;

         if (k==6) System.out.println();
      }

      System.out.println();
      System.out.println();

   }

   static double Left ()
   {
      return 0.0;
   }

   static double Right ()
   {
      return 100.0;
   }

}

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Thanks!  I like the first set of anti-war slogans especially.  Also,
it is interesting for me, as an American, to read about the British
protests -- especially since they are having some effect on the
government (though not enough, yet).  Your note of optimism was a nice
way to conclude.

Great explanation and support links -- Thanks!!!

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Thanks for your help, good thoughts and ideas - what I was looking. 
Interesting about how the search engine transforming the text before
indexing it.  Quite thorough.

Great job!  Thanks!