Many thanks for the help!

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Perfect.  Thank you.

thanks this was very helpfull

exactly what i needed - first time I have used google answers and am def impressed

Very complete and accurate. Thanks!

This was a very detailed answer that not only help solve my problem
but also help in solving other minor problems.

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We'll do business again in the future.

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excellent work

great, thanks for all the follow up links...

GREAT JOB ANSWERING THE QUESTION!  $5.00 well spent! How does google
prevent the usage of GA by students, in order to complete homework
problems???  (As I may have possibly JUST done.)

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I am so sorry I didn't reply sooner. These are the sites I really need to see!
If I didn't ask to google about Boolean algebra, I wouldn't have found
out. I'm taking an online class, and  we're expected to get our own
resources. I'm so glad I was able to recieve such a good and clear
response to my question. I don't have to worry that I won't understand
the topics that are assigned. Hooray!

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excellent choices.  thanks

Dear livioflores-ga. Thank you for an excellent job! I have tried for
so long to get such maps. I have asked all kinds of friends who
supposedly know about this kind of stuff, but you filled the bill!!

Keep an eye for me. I got lots of questions!

God bless you to know and do His will!

John P

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Thanks. If you want to find a 1-page answer to this question that would be cool =)

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Wonderful answer, and so fast, too!

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I was ovrwhelmed with the wonderful answer. My search was done on the
subject of Venn diagrams.

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All the information I have requested are answered with indept
information, the conclusion is a great one as well. Thanks for now

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Thank you very much for the informaton. It's really good.

just what we needed thanks much!

Excellent, excellent, excellent!

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Thanks.  Sorry took so long to rate -- I'm not great with math, so took awhile 
to understand it for myself.

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excellent

OUTSTANDING

Exactly what i was looking for!

Great answer, livioflores... perfect.  I'll use it.  (I do have to
work out the case for n variables rather than two, but I assume that
is easy to do in a spreadsheet, using associativity, correct? (like
(sd(x+y+z) = sd((x+y)+z))

I'm adding a tip not only because it is a good answer with good
references, but because I'd love a pointer to someplace that explains
the geometric/trigonometric connection with all this.  After all, we
are certainly looking at hypoteneuses, cosines and such here, right?

Thanks. --David Lewis

That was good. I appreciate. keep it up!