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Q: Communication system ( No Answer,   1 Comment )
Question  
Subject: Communication system
Category: Science > Physics
Asked by: cpwong-ga
List Price: $2.50
Posted: 05 Nov 2002 22:33 PST
Expires: 05 Dec 2002 22:33 PST
Question ID: 100112
My question is about communication system show below.

"Calculate the thermal noise power in both watts and dBm for the
following amplifier bandwidths and temperatures (a)B=100Hz,T=17 degree
C (b)100kHz,T=100 degree C".Thank!
Answer  
There is no answer at this time.

Comments  
Subject: Re: Communication system
From: jhouse-ga on 05 Dec 2002 09:47 PST
 
if T = noise temperature, kT = Watts/Hz for the noise.

Therefore,
E = kTB

and by definition,
dBm = 10 * log ( E / (1 milliwatt) )
(log is base 10)

I'm sure that should be in your text book.

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