I need the exact c language code for the following. Write a program
that initializes an array of double and then copies the contents of
the array into two other arrays.( All three arrays should be declared
in the main program.)
To make the first copy, use a function with array notation. To make
the second copy, use a function with pointer notation and pointer
incrementing. Have each function take as arguments, the name of the
target array, and the number of elements to be copied. That is the
function calls would look like this, given the following declarations:

double source[5]= {1.1, 2.2, 3.3, 4.4, 5.5,};
double target1[5];
double target2[5};
copy_arr(source, target1, 5);
copy_ptr(source, target1, 5);

Thank you for the question.

I have implemented the required specification and included the file
below.

Here is the script:

% gcc copy.c
% ./a.exe
Success

Here is the file copy.c . I have also placed a copy of this file at:

http://www.rbnn.com/google/copy.c 

since sometimes program codes do not render correctly.

As always, if you would like additional features or have any
questions, please solicit these using the "request clarification"
button in your browser before rating the answer.

-----------INCLUDED FILE copy.c---------

#include <stdlib.h>

void copy_arr(double source[], double target[], int len){
  int i;
  for (i=0;i<len;++i)
    target[i]=source[i];
}

void copy_ptr(double * source, double * target, int len){
  int i;
  for (i=0;i<len;++i)
    *target++=*source++;
}

int main(){

  double source[5]= {1.1, 2.2, 3.3, 4.4, 5.5,}; 
  double target1[5]; 
  double target2[5]; 
  int i;
  int error=0;
  copy_arr(source, target1, 5); 
  copy_ptr(source, target2, 5);

  for (i=0;i<5;++i)
    if (source[i]!=target1[i]||
	source[i]!=target2[i]){
      printf("Error at: %d\n",i);
      error=1;
    }
  if (error)
    printf("Failure\n");
  else
    printf("Success\n");

}