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Subject:
heat generation fluid friction
Category: Science > Physics Asked by: 3rrotec-ga List Price: $20.00 |
Posted:
20 Nov 2002 15:26 PST
Expires: 20 Dec 2002 15:26 PST Question ID: 111553 |
Interested in any research on generating steam from water using high velocities and resonable pressures. Need rpm's, volumes of water, horsepower input etc. If answers are satisfactory more questions will follow. A typical example is pumping water thru a centrifugal pump right back into the suction side. Heat generated will burn up the seals. Thanks! 3rrotec | |
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Subject:
Re: heat generation fluid friction
Answered By: hedgie-ga on 30 Nov 2002 03:41 PST Rated: |
3rrotc Answer to your question is yes, aproximately. The numbers I am getting based on two data 1) Latent heat of evaporation for water = 2.5 kJ per g (see https://answers.google.com/answers/main?cmd=threadview&id=114825 2)1 gallon ~ 3.78 l has mass about 3.78 kg and weight ~ 8.33 lb Your requirement 7289 lb per hour is 3307.5 kg/h = .91875 kg/s (kg/s =kilogram per second) using conversion 2. Using constant 1) that requires 2.29 MW (mega watts) of power. Converting MW to HP ( 1HP=750W) we get 3065 H.P. engine. This is reasonably close to your number 2760, considering that density of water depends on temperature and we are assuming 100% efficiency. hedgie |
3rrotec-ga
rated this answer:
Good answer. |
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Subject:
Re: heat generation fluid friction
From: neilzero-ga on 20 Nov 2002 15:52 PST |
This seems like the reverse of what we do in a steam turbine: Is it possible to turn a small "off the shelf steam turbine" in the reverse direction with a motor while spraying (low pressure) cold or warm water into what is normaly the exhaust end and get hot high presure steam from what is normally the input end. This should not stress = damage the turbine. If it works even slightly, a more efficient design should be possible. I'm just guessing = brainstorming. Neil |
Subject:
Re: heat generation fluid friction
From: 3rrotec-ga on 24 Nov 2002 04:23 PST |
Sorry for delay. Hard drive problems. According to Machinery's Handbook 1 hp is equal to 2.64 lbs. water evaporated per hour. If desired quanity of water is 7289 lbs per hour: 7289/2.64=2760 hp per hour. Does this mean we have to run a 2760 hp engine for one hour to evaporate 875 gallons of water assuming 100% efficiency? If you agree we should use cord wood! If you disagree please explain. Thanks! 3rrotec |
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