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Q: Chemistry Equilibrium ( Answered 4 out of 5 stars,   1 Comment )
Question  
Subject: Chemistry Equilibrium
Category: Science > Chemistry
Asked by: princess2-ga
List Price: $20.00
Posted: 05 Dec 2002 12:22 PST
Expires: 04 Jan 2003 12:22 PST
Question ID: 119884
A 0.030 M solution of a weak monoprotic acid is 0.50% ionized.  What
is the percent ionization of a 0.30 M solution of the acid?

Request for Question Clarification by websearcher-ga on 05 Dec 2002 13:11 PST
Hi princess2:

I have found the actual answer to this question. However, I don't know
how the answer was derived. Do you need to know the steps, or is just
the percentage enough?

Thanks. 

websearcher-ga

Clarification of Question by princess2-ga on 05 Dec 2002 14:29 PST
I was hoping to get the steps to the final answer, because I have the
final answer, but don't know how to get to it.  Thanks.

Request for Question Clarification by tehuti-ga on 05 Dec 2002 15:06 PST
According to the information on
http://newark.rutgers.edu/~rogerlal/chem116/chap18lec2.htm you need
the Ka value to make this calculation.  Is this a value you have, and
if yes, is this an acceptable answer?

Request for Question Clarification by tehuti-ga on 05 Dec 2002 15:09 PST
Actually, I believe that you can substitute the information you have
been given on the % value at 0.030M to obtain the Ka, and then use it
to derive the answer.  Would you agree this is the answer you need in
order to find how to solve the question?

Clarification of Question by princess2-ga on 05 Dec 2002 19:57 PST
I got it!  Thanks!
Answer  
Subject: Re: Chemistry Equilibrium
Answered By: tehuti-ga on 06 Dec 2002 01:46 PST
Rated:4 out of 5 stars
 
The information at http://newark.rutgers.edu/~rogerlal/chem116/chap18lec2.htm
includes an equation which shows the relationship between molar
concentration, percentage ionization and the Ka (dissociation
constant) of the weak acid. The Ka can be calculated using the values
given in the first part of the question. The Ka value is then placed
into the equation together with the second value for the molar
concentration, and this enables the percent ionization for that
concentration to be calculated.

Thank you, livioflores, for your courtesy and honesty :) It has been
such a long time since I dealt with chemistry problems, so I was
nervous about claiming the answer!
princess2-ga rated this answer:4 out of 5 stars
I really liked how quickly someone responded to my question and I had
the answer within a couple of hours.

Comments  
Subject: Re: Chemistry Equilibrium
From: livioflores-ga on 05 Dec 2002 22:43 PST
 
I can post the answer, but I think that tehuti come first!!
Answer this question tehuti, you are right!!
Bad luck for me.

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