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| Subject:
logic
Category: Arts and Entertainment Asked by: fido123-ga List Price: $2.50 |
Posted:
31 Dec 2002 14:26 PST
Expires: 30 Jan 2003 14:26 PST Question ID: 135702 |
If all chess players are intelligent, and if all intelligent people have black hair, then all chess players have black hair. True of false |
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| Subject:
Re: logic
Answered By: answerguru-ga on 31 Dec 2002 15:00 PST Rated:  |
Hi fido123-ga, The answer is TRUE. The key to obtaining this answer is recognizing that ALL chess players are intelligent, and that ALL intelligent people have black hair. Consider any arbitrary chess player....we immediately know that they are intelligent. As a result of being intelligent, it is known that they will have black hair. Cheers! answerguru-ga |
| fido123-ga
rated this answer:
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| Subject:
Re: logic
From: cipher17-ga on 01 Jan 2003 05:33 PST |
C -- set of chess players
I -- set of intelligent people
B -- set of people having black hair.
Given: C is subset of I (needn't be proper)
I is subset of B (needn't be proper)
implies: C is subset of B.
Hence all chess players have black hair. |
| Subject:
Re: logic
From: jbf777-ga on 06 Jan 2003 21:35 PST |
I believe this is called the Law of Syllogism. I'm not entirely positive on this, however. |
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