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Q: VIBRATION ( Answered,   0 Comments )
Question  
Subject: VIBRATION
Category: Science > Technology
Asked by: wjs-ga
List Price: $25.00
Posted: 09 Mar 2003 15:47 PST
Expires: 08 Apr 2003 16:47 PDT
Question ID: 173969
Find the natural frequencies and modes for the system whose matrices
are given below.Normalize the modes so that the largest term in each
vector is
1.0.Sketch the mode shapes.Find the modal matrx[‚`].
M=[1 0;     K=[2 -1;
   0 1]        -1 2]

Clarification of Question by wjs-ga on 09 Mar 2003 17:59 PST
Find the natural frequencies and modes for the system whose matrices
are given below.Normalize the modes so that the largest term in each
vector is 1.0.Sketch the mode shapes.Find the modal matrx[A]. 
M=[1 0;     K=[2 -1; 
   0 1]        -1 2]
Answer  
Subject: Re: VIBRATION
Answered By: googlenut-ga on 09 Mar 2003 23:28 PST
 
Hello wjs-ga,

The mass and stiffness matrices in your problem describe a two
degree-of-freedom system.

A good reference for solving for the natural frequencies and mode
shapes for a two degree-of-freedom system can be found at:

University of Saskatchewan, College of Engineering
http://www.engr.usask.ca/classes/CE/804/notes/mdof_dis.pdf


As described in this reference, for this type of system, the mass
matrix is given by

[m1  0
0   m2]

The stiffness matrix is given by

[k11  k12
 k21  k22]

(See Eq. 8.2a in the reference)


k11 = k1 + k2;  k12 = -k2

k21 = -k2;  k22 = k2

(See Eq. 8.3)


Based on the information that you have provided in your problem,

m1 = 1;   m2 = 1

k11 = 2;  k12 = -1;  k21 = -1;  k22 = 2


With this information, you can use Eq. 8.8 to calculate the natural
frequencies:


(w1)^2=1/2[(2/1)+(2/1)]-SQRT[1/4(((2/1)-(2/1))^2)+((-1)^2)/(1)(1))


(w2)^2=1/2[(2/1)+(2/1)]+SQRT[1/4(((2/1)-(2/1))^2)+((-1)^2)/(1)(1))


(I hope that’s not too confusing. It’s a little difficult to make the
equation readable.)


This gives you w1^2 = 1 and w2^2 = 3

Therefore the natural frequencies are w1 = 1 and w2 = SQRT(3) = 1.732.


Eq. 8.9 gives you the mode shapes:

First mode shape:

[Q1         K12            -1           -1
 --  = ------------- = ------------ =  ----- 
 Q2]1   m1(w1)^2 –k11   (1)(1)^2 – 2    -1


As stated in the reference, Q1 can be arbitrarily set to one.

Therefore if Q1 = 1, then Q2 = 1.  The masses are moving in phase.


I’ll try to plot it, but I don’t know how this is going to look after
it is posted.

  m1     m2
  .______.	
 /        \
/          \



Second mode shape:

[Q1         K12            -1                   -1
 --  = ------------- = --------------       =  ---- 
 Q2]2   m1(w2)^2 –k11  (1)(SQRT(3))^2 – 2        1


Therefore if Q1 = 1, then Q2 = -1.  The masses are moving
out-of-phase.

  M1
 /\    
/--\--/
    \/
     m2


The modal matrix is

[1   1
1   –1]


Other references:

Kettering University
http://www.gmi.edu/~drussell/Demos/multi-dof/multi-dof.html

Structural Dynamics Research Laboratory
University of Cincinnati
http://www.sdrl.uc.edu/ucme662/lectures.pdf

Mechanical Engineering Department
United States Naval Academy
http://web.usna.navy.mil/~ratcliff/EM423/MDOF/Twodof.pdf

Mechanical Vibrations, Second Edition, Singiresu S. Rao
Addison-Wesley Publishing Company, 1990


I hope this has been helpful.  If you have questions, please request
clarification prior to rating the answer.

Googlenut


Google Search Terms:

spring mass mode shapes "two degree of freedom"
://www.google.com/search?hl=en&lr=&ie=ISO-8859-1&safe=off&q=spring+mass+mode+shapes+%22two+degree+of+freedom%22

natural frequencies mode shapes
://www.google.com/search?q=natural+frequencies+mode+shapes&btnG=Google+Search&hl=en&lr=&ie=ISO-8859-1&safe=off
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