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Subject:
measure with densities
Category: Science > Math Asked by: madukar-ga List Price: $12.00 |
Posted:
30 Apr 2003 11:20 PDT
Expires: 06 May 2003 22:36 PDT Question ID: 197536 |
Let (X,M,mu) be a measure and let phi: X to [0,infinity] be M measurable. Define nu(E):= integral over E phi dmu for E belongs to M. verify the followng statements: 1) nu is a measure on M. 2) If F is M- measurable and non-negative then integral fdnu= integral fphidmu. 3) Let F be any M-measurable function(extended real or complex valued). Then f is nu - integrable if and only if f phi is mu-integrable. If so the formula in b) holds again. Here PHI is called a DENSITY of nu with respect to mu. nu is called the measure with mu-density phi. |
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