Having watched some snooker recently (World championship at the
Crucible theatre ) I am curious what the results of the following
situations would be

 Player is playing for a red. He hits a red ball which then hits a
pink
 ball. the pink ball then hits another red. In the process both reds 
 are pocketed (but not the pink)
 What would the result be?

 Player is playing for pink. Then pink hits a red and both the pink
and
 red are pocketed. What is the result?
  
 Player is playing for BLUE (BLue ,pink and black remaining)
 Blue hits pink. Both Blue and Pink balls pocketed.
 What is the result? Also what balls if any are returned to the 
 table?
  Kind regards 

  Mongolia

Hello mongolia,

Thank you for your question.

I've always been intrigued with Snooker, and though I've played
countless pool, nine ball and eight ball games in my life, I have
never had the opportunity to play at Snooker.

Billiard World has the rules of Snooker and answers your questions:
http://www.billiardworld.com/snooker.html

"Player is playing for a red. He hits a red ball which then hits a
pink  ball. The pink ball then hits another red. In the process both
reds are pocketed (but not the pink).
 
What would the result be?"

Answer:

"...1. A legally potted ball entitles the striker to continue at the
table until he fails to legally pot a ball.

2. On all shots, the striker must comply with the appropriate
requirements of Rules of Play 5 and 6. It is not necessary to cause
the cue ball or an object ball to contact a cushion or drop in a
pocket after the cue ball has contacted a legal object ball (ball on).
Failure to contact a legal object ball first is a foul.

3. As long as reds are on the table, the incoming striker (player
taking his first stroke of an inning) always has a red as his legal
object ball (ball on).

4. Any red balls potted on a legal shot are legally potted balls; the
striker need not call any particular red ball(s), pocket(s) or details
of how the pot will be played.

5. When the striker has a red ball as his "ball on" (legal object
ball), he must cause the cue ball's first contact to be with a red
ball. Failure to do so is a foul (See Penalties For Fouls)..."

So, in this case, hitting a red first and causing two reds to be
pocketed is a legal shot and both count for the player. He is then
able to shoot for a colored ball:

".... 6. After the striker has scored a red ball initially, his next
legal object is a color, and as long as reds remain on the table he
must alternate his play between reds and colors (though within each
group he may play a ball of his choice). When reds remain on the table
and a color is his object, the striker must (a) designate prior to
stroking which color ball is his object (that specific color is then
his "ball on"), and (b) cause the cue ball's first contact with a ball
to be with that colored ball. If the striker fails to meet these
requirements, it is a foul (See Penalties For Fouls)..."

Your second question:

"Player is playing for pink. Then pink hits a red and both the pink
and  red are pocketed. What is the result? "

Answer:

"...8. If the striker's ball on is a color, and he pots any other
ball, it is a foul..."

And third:

"Player is playing for BLUE (Blue, pink and black remaining) 
Blue hits pink. Both Blue and Pink balls pocketed. What is the result?
Also what balls if any are returned to the table?"

Answer:

"8. If the striker's ball on is a color, and he pots any other ball,
it is a foul."

So one must only pocket the proper colored object ball on a stroke.

And...

"10. While reds remain on the table, each potted color is spotted
prior to the next stroke (see Spotting Balls below for spotting
rules). After a color has been spotted, if the striker plays while
that ball is incorrectly spotted (and opponent or referee calls it
before two such plays have been taken), the shot taken is a foul. If
the striker plays two strokes after such error without its being
announced by opponent or referee, he is free of penalty and continues
playing and scoring normally as though the spotting error simply had
not occurred. The striker is responsible for ensuring that all balls
are correctly spotted before striking. If the striker plays while a
ball(s) that should be on the table is not a foul may be awarded
whenever the foul is discovered during the striker's inning. Any
scoring prior to the discovery of the foul will count.

11. When no reds remain on the table, striker's balls on become the
colors, in ascending numerical order (2,3,4,5,6,7). These legally
potted colors are not spotted after each is potted; they remain off
the table. (The black (7) ball is an exception in the case of a tie
score; see Scoring.)...

and...

Reds illegally potted are not spotted; they remain off the table.
Colors illegally potted are spotted..."

In the case of a tie and the black ball:

"...if, however, only the black (7) ball is left on the table, the
frame ends with the first score or foul. If the players' scores are
equal after that scoring, the black is spotted on its original
position and the layers lag or draw lots for the choice of playing at,
or assigning opponent to play at, the black ball with the cue ball in
hand within the Half Circle, first score or foul then ends the
frame..."



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rules of snooker


I trust my research has answered your snooker questions. If a link
above should fail to work or anything require further explanation or
research, please do post a Request for Clarification prior to rating
the answer and closing the question and I will be pleased to assist
further.

Regards,

-=clouseau=-