

Subject:
GCF AND LCM
Category: Reference, Education and News > Homework Help Asked by: skeeter1ga List Price: $2.00 
Posted:
25 May 2003 18:18 PDT
Expires: 24 Jun 2003 18:18 PDT Question ID: 208664 
FIND THE GCF (GREATES COMMON FACTOR) AND THE LCM (LEAST COMMON MULTIPLE) OF 100, 150, 200 

Subject:
Re: GCF AND LCM
Answered By: funkywizardga on 25 May 2003 19:06 PDT 
The least common multiple (other than 1) is easy, since each number is divisible by two. 2 is the smallest multiple common to all 3 numbers. One link I found shows the method to finding greatest common factors "Factoring  Greatest Common Factor (GCF)  First Glance" from math.com ( http://www.math.com/school/subject1/lessons/S1U3L2GL.html ) It says to "1. List the prime factors of each number. 2. Multiply those factors both numbers have in common. If there are no common prime factors, the GCF is 1." So, for the problem given, the greatest common factor would be 50 100: 2*2*5*5 150: 2*3*5*5 200: 2*2*2*5*5 So, those multiples in common of each number would be: 2*5*5 or 50 I hope this fully answers your question. If anything is unclear, please ask for a clarification and I will be glad to assist. Search strategy: ://www.google.com/search?hl=en&lr=&ie=ISO88591&safe=off&q=greatest+common+factor 

Subject:
Re: GCF AND LCM
From: websearcherga on 25 May 2003 19:20 PDT 
Hi skeeter1: In a similar vein, the LCM (least common multiple) takes the values in the prime factorizations and includes just enough factors such that all the factors from each number can be found in the result. In other words: 100: 2*2*5*5 150: 2*3*5*5 200: 2*2*2*5*5 LCM(100,150,200) = 2*2*2*3*5*5 = 600 This is the smallest number that each of 100, 150, and 200 divide into evenly. websearcherga 
Subject:
Re: GCF AND LCM
From: funkywizardga on 25 May 2003 19:23 PDT 
Thanks websearcher for making up for my confusion. I must have been thinking least common multiple was another name for least common denominator. Again, thanks for helping in this matter. 
Subject:
Re: GCF AND LCM
From: websearcherga on 25 May 2003 19:51 PDT 
No problem at all funkywizard. I just figured you missed that part of the question. :) Anytime. websearcherga 
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