Calcium chloride and water react according to the following equation:
CaCl2 + H2O ----> CaO + 2HCL. How much hydrogen chloride would be
produced from 87.4 g of calcium chloride?
a. 84.9 g
b. 57.4 g
c. 28.7 g.
d. 175 g

Helloooo!!!


Remember the answer to one of your previous question (Question ID:
226334); the balanced equation CaCl2 + H2O ----> CaO + 2HCL means that
in this reaction you will need 1 mol of CaCl2 to obtain 2 moles of
HCL.

The atomic weights involved in this problem are:
Ca : 40.078g
Cl : 35.453g
H  :  1.008g

Then the molecular weight are:
CaCl2 : 40.078g + 35.453g * 2 = 110.984g (and this is the weight of 1
mol).
HCl   :  1.008g + 35.453g = 36.461g (and this is the weight of 1 mol).

Ok, now we are ready to solve the problem:

From 110.984g of CaCl2 we obtain 2x36.461g = 72.922g of HCl, then from
87.4g of CaCl2 we will obtain (87.4 x 72.922)/110.984 = 57.426g of
HCl.

The correct answer is b) 57.4 g.

Hope this helps.

Regards.
livioflores-ga