For the reaction, 3 Cu + 8HNO3---> 3Cu(NO3)2 + 2NO + 4 H2O, calculate
the number of moles of water produced when 6.6 mol of copper (II)
nitrate are formed in the reaction.
a. 4 mol
b. 6.6 mol
c. 4.9 mol
d. 8.8 mol

From the above equation, we know that four moles of water are
generated for every three moles of copper (II) nitrate formed in the
reaction.  Therefore, 6.6 moles of copper (II) nitrate multiplied by
(four moles of water/three moles copper (II) nitrate) = 8.8 moles of
water.  Therefore, the correct answer is D.

Sincerely,

Wonko