|
|
Subject:
chemistry
Category: Science > Chemistry Asked by: teatea-ga List Price: $2.00 |
Posted:
09 Jul 2003 17:25 PDT
Expires: 08 Aug 2003 17:25 PDT Question ID: 227188 |
A 100 mL sample of hydrobromic acid, HBr, is titrated to an endpoint with 24.0 mL of 1.5 N NaOH. What is the concentration of HBr? a. 1.4 N b. 0.72 N c. 3.1 N d. 0.36 N |
|
Subject:
Re: chemistry
Answered By: synarchy-ga on 09 Jul 2003 19:08 PDT Rated: |
Hello, This question follows the same logic as the previous question that I answered for you: http://answers.google.com/answers/main?cmd=threadview&id=227189 Using the equation from that question: V1 * C1 = V2 * C2 where V1 = volume solution 1 V2 = volume solution 2 C1 = concentration solution 1 C2 = concentration solution 2 The acids and bases in this question are both mono-functional (ie they have one H+ or one OH- group) so their acid/base concentration is given by the concentration of the parent compound. Thus, plugging in numbers: V1 = 100 mL C1 = x V2 = 24.0 mL C2 = 1.5 N 100 mL * x = 24.0 mL * 1.5 N and rearranging: 24.0 mL * 1.5 N x = ---------------- = 0.36 N HBr 100 mL Here is a nice javascript demonstration of the principles employed: http://michele.usc.edu/java/acidbase/acidbase.html Google search titration example |
teatea-ga rated this answer: |
|
There are no comments at this time. |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |