0.050 mole of a gas was collected in the lab at a temperature of 22.0
degrees C and a pressure of 100.0 kPa. What volume will the gas occupy
under these conditions?
a. 1.2 dm3
b. 0.09 dm3
c. 1.4 dm3
d. 0.14 dm3

Hi teatea:

The answer is "a. 1.2 dm^3".

We use the Ideal Gas Law:

   PV = nRT


So, converting to the proper units and substituting, we get:

(1 atm)* V = (0.05 moles) * (0.082058 atm/(mol * K)) * (295 K)

V = 1.20 L = 1.20 dm^3


For more details on conversions and the formula see:

Gas Laws
URL: http://www.shodor.org/unchem/advanced/gas/


Hope this helps. 

websearcher-ga


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