How many earths would fit inside Jupiter?  And what is calculation to
figure this out?

Hi knowledge007:

Thanks for the interesting question!


The answer to your question depends upon exactly what you mean by "fit
inside."

If you just mean "how many time larger, by volume" is Jupiter, the
answer is straightforward. You simple take the ratio of the radii of
Jupiter and the Earth and cube it (i.e., multiply it by itself three
times).

Radius of Jupiter = 69911 km
Radius of Earth   =  6371 km

66911
----- = 10.97
 6371

10.97^3 = ~1320

So, the volume of the Earth would fit inside the volume of Jupiter
about 1320 times.


However, if you wanted to "pack Earth-sized spheres inside" the volume
of Jupiter, you need to account for the "empty space" between the
spheres. It has been mathemtically shown that the densest posible
packing of smaller spheres within a larger sphere only "wastes" about
25% of the space.

So, this means that you could fit about 990 (1320*.75) Earth-size
spheres within Jupiter.


Sources: 

Planets: Physical Data 
URL: http://ssd.jpl.nasa.gov/phys_props_planets.html

Packing Spheres
URL: http://mathforum.org/library/drmath/view/55181.html

I hope this information helps with your research.   
                            
If you need any clarification of the information I have provided,
please ask using the clarification feature and provide me with
additional details as to what you are looking for. As well, please
allow me to provide you with clarification(s) *before* you rate this
answer.
                            
Thank you.                             
                            
websearcher-ga                             
                                              
  
Search Strategy (on Google):    

planets data radius 
"packing spheres" "larger sphere"