A eudiometer contains a 65.0 ml sample of a gas collected by the
displacement of water. The water levels inside and outside the
eudiometer are the same. The atmospheric pressure is 92.5 kPa and the
temperature is 23 degrees C. What volume will the dry gas occupy at
STP? The vapor pressure of water at 23 degrees
C is 2.8kPa

Assuming the gas behaves as an ideal gas over this range of
temperatures and pressures,

Standard Temperature and Pressure is equal to 273K 101.325 kPa.  23°C
= 296.15K

From the ideal gas law, we know that V2 = T2/T1 X P1/P2 X V1.

P1 equals the pressure of the gas sample which equals the total
pressure in the eudiometer minus the partial pressure of the water. 
The total pressure is 92.5 kPa, and the vapor pressure of water is
given to be 2.8 kPa, so P1 = 89.7 kPa.

Therefore,

V2 = 273/296.15 X 89.7/101.325 X 65.0 = 53.0 ml.

Source:

Chemical Principles, fourth edition, by Dickerson, Gray, Darensbourg,
and Darensbourg, The Benjamin/Cummings Publishing Company, Inc., 1984
Sincerely,

Wonko