Hi again teatea!
In this case, we can first calculate pOH (hydroxide ion concentration)
and from there, calculate pH (hydrogen ion concentration). The formula
for pOH is similar to th one of pH:
pOH = -log(OH-)
where OH- is the hydroxide ion concentration measured in mol L-1 (M).
In order to calculate pOH, first we write the equation for the
dissociation of KOH:
KOH ----> K+ + OH-
Since KOH is a strong base that fully dissociates, then 0.0058 M KOH
gives 0.0058 M OH-. Therefore,
pOH = -log(0.0058) = 2.23
Finally, since we know that pH + pOH = 14, then
pH = 14 - pOH = 14 - 2.23 = 11.76
Check the following page for more information on how pH and pOH is
calculated.
Defining pH
http://www.ausetute.com.au/phscale.html
Google search strategy
calculate ph
://www.google.com/search?q=calculate+ph&hl=en&lr=&ie=UTF-8&oe=UTF-8&start=10&sa=N
I hope this helps. If you have any doubt regarding my answer, please
request a clarification before rating it. Otherwise, I await your
rating and final comments.
Best wishes!
elmarto |
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