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Subject:
chemistry
Category: Science > Chemistry Asked by: teatea-ga List Price: $2.00 |
Posted:
17 Jul 2003 13:29 PDT
Expires: 16 Aug 2003 13:29 PDT Question ID: 232141 |
One dm3 of a solution was prepared containing 0.0040 mole of Pb(NO3)2. The Ksp of PbCl2 for the existing conditions is 2.4 x 10-4. F rom the list below, choose the smallest number of moles of NH4Cl that when added to this solution will cause PbCl2 to precipitate. (Assume no increase in volume). a. 0.25 mole b. 0.30 mole c. 0.20 mole d. 0.15 mole |
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Subject:
Re: chemistry
Answered By: wonko-ga on 17 Jul 2003 16:00 PDT Rated: |
http://scidiv.bcc.ctc.edu/wv/002-10.html "Online Introductory Chemistry" Dr. Walt Volland, Bellevue Community College 1L = one cubic decimeter Therefore, the concentration of the Pb(NO3)2 solution is 0.004M. Ksp = [Pb] [Cl]^2 = 2.4 x 10-4 Therefore,[Cl] = (2.4 x 10-4/0.004)^1/2 = 0.25M Because one mole of NH4Cl produces one mole of chloride ions and the quantity of solvent is 1 L, the number of moles of NH4Cl is equal to the concentration multiplied by the volume (1L) = 0.25 moles (Answer A). Sincerely, Wonko Additional source used: Chemical Principles, fourth edition, Dickerson, Gray, Darensbourg, and Darensbourg, The Benjamin/Cummings Publishing Company, Inc., 1984 |
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