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Subject:
science
Category: Miscellaneous Asked by: webweaverlady-ga List Price: $3.00 |
Posted:
17 Jul 2003 16:57 PDT
Expires: 16 Aug 2003 16:57 PDT Question ID: 232246 |
When we look at the light curve for an eclipsing binary system with total eclipses, how can we tell which star is hotter? |
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Subject:
Re: science
Answered By: wonko-ga on 17 Jul 2003 17:32 PDT Rated: ![]() |
"The analysis of the minimum of the light curve corresponding to the primary eclipse would yield several important parameters. We obtained the distance d to the binary system. Then the ratio of the relative depths of the minima (in terms of the apparent visual magnitudes mv) gives us the ratio of the absolute visual magnitudes Mv through the modulus equation: Mv= mv - 5log10d - 5 + A The ratio of the absolute visual magnitudes then gives a ratio of luminosities if we use the relation: M = Msun - 2.5 log10(L/Lsun) Finally this, with the Stefan Boltzman law: L = 4 pi sigma r^2 T^4 gives a ratio of the temperatures (Tl/Ts)^4 where Tl is the effective temperature of the larger companion and Ts that of the smaller." http://www.macalester.edu/astronomy/research/phys40/momar/webpage.html "A study of eclipsing binary systems." by Momar Dieng sincerely, Wonko |
webweaverlady-ga
rated this answer:![]() Terrific! |
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