Write a balanced chemical equation for the reaction between H2SO4 and KOH.
b. Write the ionic equation fot the reaction.
c. Write the net ionic equation for the reaction.

Hello teatea!
Here are the answers to your questions. 

a. We know that an acid-base reaction will form water and a salt. We
know that KOH dissociates as K(1+) and OH(1-). Also, H2SO4 dissociates
as 2 H(1+) and SO4(2-). So OH(1-) and H(1+) form H20 water (leaving us
with a free H). Thus we need another molecule of KOH in order to
balance the equation. The 2 K(+1) and SO4(-2) will form K2SO4. The
balanced equation is then:

2 KOH + H2SO4 ---> 2 H20 + K2SO4

b. It's now easy to write the net ionic equation

2 K(1+) + 2 OH(1-) + 2 H(1+) + SO4(2-) ----> 2 H20 + 2K(1+) + SO4(2-)

c. Cancelling the 2 K(1+) and SO4(2-) from both sides of the ionic
equations leaves us with the net ionic equation

2 OH(1-) + 2 H(1+) -----> 2 H20

To learn more about balanced chemical equations, ionic equations and
net ionic equations, check:

Balanced Chemical Equations
http://server.chem.ufl.edu/~itl/2045_s99/lectures/lec_3.html

Balancing Ionic Equations
http://www.cofc.edu/genchemlab/ionic.htm

Net Ionic Equation
http://www.iun.edu/~cpanhd/C101webnotes/chemical%20reactions/netioniceq.html


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Best wishes!
elmarto