Hi. I would like to write an autorun.inf file that will open an mpg
file when the cd is inserted into the drive. There will only be three
files on the cd, a filename.mpg, a filename.mov and the autorun.inf.
So far I have copied and edited another autorun.inf file to the
following:
[AutoRun]
OPEN=filename.mpg
label=filename
I have written the three files to a cd and the autorun isnt working.
What am I doing wrong? Any help on this is greatly appreciated.
Thank you.

Hello philbert-ga,

It appears that your problem is with the 'OPEN=' statement. This
statement will only work with executable programs on your CD (*.exe).
If you are trying to open a data file (in this case a video) with the
default program on the user's computer, you need to use the
ShellExecute command as follows:

[autorun]
ShellExecute=filename.mpg
icon=filename.mpg

However, there is a slight caveat; the ShellExecute command does not
work on all versions of Windows, so you can also use this equivalent
command:

[autorun]
open=command /c start filename.mpg
icon=filename.mpg

http://www.cryer.co.uk/brian/windows/howtocacdtwar.htm

There is also a way to test your autorun.inf file without burning a CD
- the details are available at:
http://www.cryer.co.uk/brian/windows/howtotcdaurwobacd.htm

Hopefully this helps you in your quest...happy autorunning!

answerguru-ga
Google Answers Researcher

Excellent. Thanks for your help.