Clarification of Question by
marsal-ga
on
03 Sep 2003 01:17 PDT
Hi mathtalk-ga,
Thanks for your message.
Actually, since I pick fractions (and let them go to zero, which I
didn't write previously) from the urn, I think the distribution will
be continuous.
For example, if I would pick fractions of tenths, then two picks (i.e
n=0.2) could lead to x/n being 0, 0.5, or 1.
If I let n be constant, but decrease the size of the fractions to
twentieths, then I must make four picks to fill the "group". This
could lead to x/n being 0, 0.25, 0.5, 0.75, or 1.
The idea is then that the fraction goes to zero, which I think would
imply that the distribution becomes continuous.
I hope this is correct. I'm sorry I was a bit unclear in the original
question.
When it comes to approximating the distribution with the normal
distribution, it would unfortunately not help me. What really
interests me with this distribution are in fact the cases when it is
not normally distributed. (i.e. n<25 and/or large imbalance between N1
and N2)
Thanks again for your help.
marsal-ga