A doctor orders your patient 3g potassium chloride in 1000mls of
normal saline. What amount in mls of potassium chloride 20 mmol in 10
mls are you going to put in the IV bag? Information needed ; molecular
mass potassium =39g/mol. Molecular mass chloride = 35g/mol

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Request for Question Clarification by boquinha-ga on 28 Aug 2003 22:24 PDT

Could you please clarify in what unit of measure you would like the
result to be expressed. Did you mean mg of KCl, or perhaps mols?

Hi aquarius21!!

1 mol of KCl weights:
(39g + 35g) = 74g

Then 20mmol (0.020 mol) of KCl weights:
74g * 0.020mol = 1.48g

So we have 1.48g (=20mmol) of KCl per 10ml (this is the available
solution) and we need 3g of KCl, to know the amount of ml (of the
available solution) that contain 3g of KCl:
1.48g __________ 10ml
3.00g __________  Xml = 3.00g * 10ml / 1.48g = 20.27ml

So to put 3g of KCl in the IV bag you must put 20.27ml of the "20 mmol
in 10
mls" solution.


It appears that you are at a Nursing course, may be the following page
will be useful to you:
"nursing calculators":
http://www.manuelsweb.com/nrs_calculators.htm


I hope this helps. If you find something unclear please ask for an
answer clarification before rate this answer, also let me know if the
answer works.

Best regards.
livioflores-ga

thankyou for your clarification of this question. My formula had a
mistake in it and I could not work out an answer that sounded
sensible. Chances are I will never have to work it out but now I know
I can if I have to. Many thanks