how to calculate the number of incorrect bits of an optical fibre
transmission of 100Gb

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Request for Question Clarification by maniac-ga on 03 Sep 2003 19:43 PDT

Hello Ross21,

What sort of bit error rate do you want to assume for this optical
fibre? A quick search finds published numbers varying from 10 ^ -9 to
10 ^ -12, the variance depends on the speed of the line, line quality,
detector quality, and so on. Would a range of values and the formula
be an appropriate answer?

  --Maniac

Could you clear up your question some more?

I do not understand why the medium on which data is transmitted is
applicable to your answer.  Even if we were using smoke stacks to
transmit 100Gb of data the calculation of the amount of errors would
still be the same.

Your answer may be more simple than you think (although I suspect it
is not).  Here is what I have laid out:

According to the google calculator:

://www.google.com/search?q=100+gigabytes+to+bits

100Gb = 858,993,459,200 bits

So now you would just simply subtract the number of bits transmitted
by the number of bits in 100Gb and you would get your answer.

(# bits transmitted) - (858,993,459,200) = # bit errors

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Let me know if this is in any way headed in the right direction, I'll
do some more looking, but I think I will need more information to help
you on this one.  Let me know!  Hope this helps!

Perhaps the line loss could be determined by the following:

DE = (Dm)c²E
E =  0.01799 (1.66 x 10 - 27 )(3 x 10 8 ) 2   [Where E is the
constant]

Otherwise it can be expressed as the following:

((1 - m2)(x2 + y2) + 2m2cx + a2 - m2c2)2 = 4a2(x2 + y2)  r = [(25 -
24tan2())/(1 - tan2())]

Hope this helps.