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Subject:
Simple Chemistry Problems #1
Category: Science > Chemistry Asked by: jwheel-ga List Price: $20.00 |
Posted:
15 Oct 2003 18:00 PDT
Expires: 14 Nov 2003 17:00 PST Question ID: 266717 |
I'm breaking a list questions into separated entries as bobbie7-ga suggested (Thank you bobbie7-ga). Please provide the answer to the following problems: 1) Suppose we let the exothermic reaction, 2SO2(g) + O2(g) <--> 2SO3(g) come to equilibrium. Then we decrease the temperature of the reaction mixture, while holding the volume constant. What will be the effect on the net amount of SO3(g) present ? 1. no change 2. a decrease 3. an increase 4. question cannot be answered without Kc or Kp values 5. question cannot be answered without delta H value 2) Consider the aqueous reaction A <--> B + C Adding a liter of water to the reaction flask will 1. not affect the number of moles of C 2. None is correct 3. increase the number of moles of C 4. decrease the number of moles of C 5. have an effect depending on the value of Kc the number of moles of C |
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Subject:
Re: Simple Chemistry Problems #1
Answered By: synarchy-ga on 15 Oct 2003 19:05 PDT Rated: |
Hello 1) In an exothermic reaction, the reaction gives off heat - therefore, by removing heat from the system, the reaction will proceed more towards reactants - a simple way to think of this is that putting in more starting material leads to more products; putting in more products, inhibits the production of products (shifts the reaction towards the reactants). Heat, here, is a product - thus less heat, more products. answer - 3 2) In this question, the equilibrium constant is given by: [C][D] k = ------- [A] if we assume a concentration of 1 to start, then: 1 * 1 k = -------- = 1 1 if we dilute the sample (assume that 1L dilutes the reaction by half), the concentrations will half (or decrease even without our assumption of half) and x will be used as the common factor for the amount of change seen. (0.5 + x)(0.5 +x) k = ------------------- solving for x gives 0.11 (0.5 - x) therefore, the concentration of C at equilibrium will be 0.61, up from the 0.5 at the time of dilution, thus, diluting the reaction will increase the concentration of the reactants, and the total number of moles of each compound. Note, this only works because the number of moles of reactant is lower than the number of moles of product which favors this direction of the reaction. answer - 3 synarchy references: description for problem 1: http://www.psigate.ac.uk/newsite/reference/plambeck/chem1/p01101a.htm a nice example for question 2: http://www.madsci.org/posts/archives/apr2001/986332923.Ch.r.html | |
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jwheel-ga
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Thank you very much, you are very helpful. |
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