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Subject:
chemistry questions part 1
Category: Science > Chemistry Asked by: jwheel-ga List Price: $50.00 |
Posted:
20 Oct 2003 14:29 PDT
Expires: 19 Nov 2003 13:29 PST Question ID: 268038 |
To make a long story short, my youngest daughter decided to endure through 4 semesters of chemistry, and now is paying up for it. She is a talented little girl, but science is not her thing and it hurts for me to see her study so hard but understand so little. It runs in the family. I wanted to help myself, but me and my wife are no scientists at all, plus it was so long ago. Tutoring is very very weak at where she goes, and we know few friends around here who are capable of helping, most of which already are looking at us the wrong way for asking so much. I decided to open my pocket and let you, Chemistry folks, help us out. I secretly took the next set of questions from my daughters assignment section, and here they are. I understand that many (or most) of you would have the problem to giving direct help like this, "learning and understanding the material is the most important", right ? Wrong. Only but a few of you would understand the pain I feel when I see my daughter quietly cry in her room over her low assignment grades after hours and hours of studying daily. Below I copied down some of the questions and choice answers that came along. I tried my best to copy down everything number to number, word for word. Its a little bit difficult to transfer everything to text, but I tried. Please feel free to clarify if you did not understand a part. I am asking for a list of answers to the problems, in numerical + content format, as such : Question 1: Answer 3. The number of moles is 4.0. Question 2: Answer 5. The reaction is reversed. Time is an issue, but I would like the answers to be correct. I do not want to check my daughters answers and tell her that one of her correct answers is incorrect simply because what was given to me is a wrong answer. Once again I apologize for such rude question, but I am desperate, and I ran out of all other options. I am also considering a big tip for those who'll work hard on these, do all (or most) of the questions, provide the correct answers and hopefully as soon as possible. Thank you once more. You are my last hope. 1) Oxalic acid is a diprotic acid with k1 = 5.9 * 10^-2 and k2 = 6.4 * 10^-5. A dilute solution of potassium hydrogen oxalate would be 1. acidic because hydrolysis of the anion would predominate over further dissociation 2. basic because further dissociation of the 3. basic because hydrolysis of the anion would predominate over further dissociation anion would predominate over hydrolysis 4. acidic because further dissociation of the anion would predominate over hydrolysis 5. neutral 2) Ka for HClO is 3.5 * 10^-8 . What is the pH of a 0.3 M solution of HClO? You may approximate the full quadratic for problem because Kc is so small. The reaction is: HClO + H2O --> H3O+ + ClO- (Kw = 1 * 10^-14). 1. 10.0 2. 3.7 3. 5.2 4. 4.0 5. 7.5 3) What is the concentration of H3O+ ions in a 0.10 M solution of Ba(OH)2, a strong elec- trolyte, at 25deg Celcius ? 1. none 2. 1.0 * 10^-1 M 3. 1.0 * 10^-13 M 4. 2.5 * 10^-13 M 5. 5.0 * 10^-14 M 4) Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 7.6 * 10^-13 at some temperature, compute the pH of a neutral aqueous solution at that temperature. Answer in units of pH. <Numerical Answer> 5) Which of the following substances is NOT a strong electrolyte? 1. HClO4 2. NH4Cl 3. NH3 4. Mg(NO3)2 5. HNO3 |
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Subject:
Re: chemistry questions part 1
Answered By: hibiscus-ga on 24 Oct 2003 18:58 PDT |
Hello again, Jwheel. I see this is the last set of your questions to get answered. I hope that all the solutions have helped you. The answers: Question 1: Answer: 4, assuming that "the anion" referred to in the question mean HOx- and not Ox^2-. Question 2: Answer: 2 HClO <-> H+ + OCl- 0.3M 0 0 (start) - x +x +x (change) 0.3 - x +x +x (equilibrium) Ka = 3.5*10^-8 = x^2 / (0.3 - x) =~ x^2 / 0.3 x = Sqrt( 3.5*10^-8 * 0.3) x = 0.00010247 pH = -Log10 x pH = 3.989, or very close to 4.0 Question 3: Answer 5 If c(BaOH2) = 0.10M [OH-] = 0.20M [H+] = 1.0*10^-14 / 0.2 = 5*10^-14 Question 4: Answer: Kw = [H+][OH-] In pure water [H+] = [OH-] So 7.6*10^-13 = x * x = x^2 x = Sqrt( 7.6*10^-13 ) x = 8.7178*10^-7 pH = -Log10 x pH = 6.05959 Question 5: Answer: 3, all others are strong electrolytes. ------------ Best of luck to your daughter. If you have any questions, please let me know. Hibiscus |
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Subject:
Re: chemistry questions part 1
From: imtiaz03-ga on 20 Oct 2003 22:05 PDT |
I just signed up right now to give a comment here. Hopefully it's not against Google policy. It should be considering my comment :) It is apparent that you love your daughter very much. You want to see her get good grades but this isn't right. You are spending some ridiculous amount of money for some simple Introductory Chemistry problems. (I took that course last year :)) If you just want the answers, why not buy the solution guide? Most of the questions you posted are "redundant" anyway - same concept. I am sure the amount of money you are willing to spend, You should be able to get a good tutor even if you believe there are none around your area. I think someone recommended you to contact the local university in one of your posts (Good idea). Anyways, it's your problem and you will do whatever you feel best. But I did feel the urgency to comment from your touchy anecdote... Peace and good luck! Another thing is She can also get help from her classmates. I am sure somebody in her class understands this crappy subject! |
Subject:
Re: chemistry questions part 1
From: omniscientbeing-ga on 22 Oct 2003 10:55 PDT |
jwheel-ga, I must say that I concur with the sentiments of imtiaz03-ga's Comment. I also took college several college chemistry courses, and I know firsthand how dikfficult this material can become, but simply having the answers to the problem sets will not make one understand how to do them. For the same asking price of your current problem sets, you could ask a different question on Google Answers that focused more on finding chemistry tutors and chemistry learning resources in your area, perhaps even your daughter's specific school. Also, you ask those who have succeeded in chemsitry courses to outline in detail their study strategies. This would be much more valuable to her in the long run than having the answers to one problem set, even if those answers are accompanied by some explanation. omniscientbeing-ga Google Answers Researcher |
Subject:
Re: chemistry questions part 1
From: p2006-ga on 09 Nov 2003 15:10 PST |
I agree with the others, buying answers was probably not the best thing to do, since the money only bought you how to do these specific problems, not any others. |
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