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Subject:
chemistry questions part 3
Category: Science > Chemistry Asked by: jwheel-ga List Price: $50.00 |
Posted:
20 Oct 2003 14:30 PDT
Expires: 19 Nov 2003 13:30 PST Question ID: 268041 |
1) Which one of the following is a weak acid? 1. HBr 2. HI 3. H2SO3 4. HClO4 5. HNO3 2) Acid rain has a pH value of 3.0, whereas normal rain has a pH value of 5.6. Calculate the ratio of the hydronium ion in acid rain to that in normal rain. <Numerical Answer> 3) In a sample of pure water, only one of the following statements is always true at all conditions of temperature and pressure. Which one is always true? 1. [H3O+] = [OH-] 2. pH = 7.0 3. [OH-] = 1.0 * 10^-7 M 4. [H3O+] = 1.0 * 10^-7 M 5. pOH = 7.0 4) Hydroxylamine is a weak molecular base with Kb = 6.6 * 10^-9. What is the pH of a 0.0500 M solution of hydroxylamine? 1. pH = 3.63 2. pH = 4.74 3. pH = 7.12 4. pH = 8.93 5. pH = 9.26 6. pH = 9.48 7. pH = 10.37 5) The [(CO2)-2] in 0.050 M H2CO3 solution (e.g. Pepsi) is? 1. 1.0 * 10^-7 M 2. 1.3 * 10^-13 M 3. 1.5 * 10^-4 M 4. 4.3 * 10^-7 M 5. 4.8 * 10^-11 M |
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Subject:
Re: chemistry questions part 3
Answered By: boquinha-ga on 21 Oct 2003 00:18 PDT Rated: |
Hello again, jwheel-ga! I wont bore you with my intro to these questions since youve already seen it. Ill just say that I hope that you and your daughter together can learn a lot from these exercises, and I hope that you both will use these answers to gain a better understanding of the concepts being quizzed. I respect your willingness to assist your daughter at a difficult time for her right now. Good luck on the assignment. - - - - - - - - - - - - - - - - - - - - - - - - - Question 1: Answer 3. H2SO3 is a weak acid (Careful! H2SO4 is not!) The Shodor Foundations Chemistry website (http://www.shodor.org/unchem/basic/ab/) states on its acid-base page that there are only 7 strong acids: HCl, HBr, HI, H2SO4, HNO3, HClO3, HClO3, HclO4 Strong acid means that the Hydrogen ion [H+] completely dissociates from its conjugate anion. - - - - - - - - - - - - - - - - - - - - - - - - - Question 2: Answer 400:1. pH = -log[H3O+] Acid rain has a pH of 3.0, so the [H3O+] is 10^-3. Normal rain has a pH of 5.6, so the [H3O+] is 2.5 x 10^-6 The ratio would be [H3O+ acid]/[H3O+ normal] = [1 x 10^-3]/[2.5 x 10^-6] = 400/1 - - - - - - - - - - - - - - - - - - - - - - - - - Question 3: Answer 1. The concentration of OH- will always equal the concentration of H3O+. Using the Ideal Gas Equation (it can be found at http://wine1.sb.fsu.edu/chm1045/notes/Gases/IdealGas/Gases04.htm) we see that Volume is related to Pressure and Temperature. PV = nRT, where R is a constant, and n is the quantity of gas measured in mols. The pH of a substance is related to the concentration of H+, so if we raise or lower the Temperature or Pressure of pure water, we will alter the Volume (or concentration) of H3O+ and OH- ions. As we alter the concentrations we alter the pH and pOH. The only answer that is true no matter what the volume or concentration may be is #1. - - - - - - - - - - - - - - - - - - - - - - - - Question 4: Answer 5. The pH is 9.26. From The Net Equation at Thinkquest.org (http://library.thinkquest.org/C004970/acidbase/concepts.htm) Kb is the dissociation constant for a base in water. For base in water, B + H2O < - - > BH+ + OH- Kb = [BH+][OH-]/[B] Utilizing a strategy from the Shodor Foundation (http://www.shodor.org/unchem/basic/ab/) we can effectively solve this problem. Hydroxylamine < - - > BH+ + OH- (it is not important to define B) Start 0.05 M 0 0 Change -x +x +x Equilibrium 0.05 x +x +x So Kb = [x][x]/[0.05 x] we can exclude - x from the denominator since it is such a small number in comparison. 6.6 x 10^-9 = x2/.05 Solving for x, x = 1.82 x 10^-5, so that is our concentration of OH- pOH = -log[OH-], so pOH = 4.74 pH + pOH = 14.0, therefore pH = 14.0 4.74 pH = 9.26 - - - - - - - - - - - - - - - - - - - - - - - - - Question 5: Answer 3. The concentration of CO2 is 1.5 x 10^-4 Using a similar strategy to question 4 above, we will use the acid-dissociation constant of carbonic acid (Ka) and a few equations to solve this problem. Ka = [H2O][CO2]/[H2CO3] H2CO3 < - - > H2O + CO2 Start .05 0 0 Change x +x +x Equil. .05 x +x +x Ka = 4.2 x 10^-7 Ka = [x][x]/[.05 x] we can exclude - x from the denominator since it is such a small number in comparison. 4.2 x 10^-7 = x2/.05 Solving for x, x = 1.5 x 10^-4 = [CO2] Acid-dissociation constant (Ka) of carbonic acid was obtained at Physchem, a South African science site. http://www.physchem.co.za/Acids/Strength.htm#Value - - - - - - - - - - - - - - - - - - - - - - - - - Again, I hope that these answers and explanation assist your daughter in her studies. Should anything be unclear, please let me know so I can clarify it for you. Sincerely, Boquinha-ga - - - - - - - - - - - - - - - - - - - - - - - - - Google Search Strategy: acid base chemistry equation conjugate acid water ideal gas equation acid dissociation constant carbonic acid | |
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jwheel-ga
rated this answer:
and gave an additional tip of:
$10.00
Hello boquinha, You get a 5 again ! Thank you very much, keep up the good job, you are very helpful. |
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Subject:
Re: chemistry questions part 3
From: hfshaw-ga on 21 Oct 2003 14:24 PDT |
Just a comment that although the answer given to question 3 ("In a sample of pure water, only one of the following statements is always true at all conditions of temperature and pressure. Which one is always true?"), is correct, the rationale boquinha-ga used to support his answer is not correct. He tried to use an argument based on the ideal gas law, a law that is not applicable to liquids, the subject of this question. (Liquid water is a particularly bad misapplication of the ideal gas law because at 1 atmpsohere, the volume of a given quantity of water actually *decreases* as the temperature increases between 0 and 4 degrees centigrade, which is the opposite behavior of all gasses and even of most condensed (liquid or solid) substances! At 1 atmosphere pressure, the density of water has a maximum at ~4 degrees centigrade.) The correct logic involves recognizing that all the possible answers 2involve the water dissociation reaction: 2*H2O(liquid) <-> H3O+(aqueous) + OH-(aqueous). As with all reactions, one can write an equilibrium constant for the reaction: K_w = [H3O+]*[OH-]/[H2O]^2 Where the brackets mean the concentrations of the species in the brackets. (Strictly speaking, these really mean thermodynamic activities, not concentrations, but this is a distinction not usually taught in high school chemistry.) By convention, the concentrations (activities) of pure substances (e.g., H2O) are defined as being equal to unity, so the equilibrium constant only involves the concentrations (activities) of hydronium and hydroxide ions. All equilibrium constants are a function of temperature and pressure. That means that the concentrations of H3O+ and OH- will vary as a function of temperature and pressure (and because pH and pOH are simply other ways of expressing the concentrations of H3O+ and OH-, they, too will vary as a function of T and P). Answer 1, the correct one, however, follows from a consideration of charge conservation. If one starts with electrically neutral water molecules, which dissociate into positive hydronium ions and negative hydroxide ions, the positive and negative charges must add up to zero (because that's what we started with.) In any sample of water, the number of positive ions (H3O+) must be equal to the number of negative charges (OH-) and [H3O+] = [OH-] (In this case, the square brackets really *do* mean concentrations, not thermodynamic activities!) |
Subject:
Re: chemistry questions part 3
From: boquinha-ga on 21 Oct 2003 17:55 PDT |
Again, thank you for the kind words, 5-star rating, and generous tip. I wish you and your daughter the best! Sincerely, Boquinha-ga |
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