Google Answers Logo
View Question
 
Q: chemistry questions part 4 ( Answered,   0 Comments )
Question  
Subject: chemistry questions part 4
Category: Science > Chemistry
Asked by: jwheel-ga
List Price: $50.00
Posted: 20 Oct 2003 14:31 PDT
Expires: 19 Nov 2003 13:31 PST
Question ID: 268042
To make a long story short, my youngest daughter decided to endure 
through 4 semesters of chemistry, and now is paying up for it. She is 
a talented little girl, but science is not her thing and it hurts for 
me to see her study so hard but understand so little. It runs in the 
family. I wanted to help myself, but me and my wife are no scientists 
at all, plus it was so long ago. Tutoring is very very weak at where 
she goes, and we know few friends around here who are capable of 
helping, most of which already are looking at us the wrong way for 
asking so much. I decided to open my pocket and let you, Chemistry 
folks, help us out. I secretly took the next set of questions from my 
daughters assignment section, and here they are. I understand that 
many (or most) of you would have the problem to giving direct help 
like this, "learning and understanding the material is the most 
important", right ? Wrong. Only but a few of you would understand the 
pain I feel when I see my daughter quietly cry in her room over her 
low assignment grades after hours and hours of studying daily. 
  
Below I copied down some of the questions and choice answers that came 
along. I tried my best to copy down everything number to number, word 
for word. Its a little bit difficult to transfer everything to text, 
but I tried. Please feel free to clarify if you did not understand a 
part. 
  
I am asking for a list of answers to the problems, in numerical + 
content format, as such : 
  
Question 1: Answer 3. The number of moles is 4.0.  
Question 2: Answer 5. The reaction is reversed.  
  
Time is an issue, but I would like the answers to be correct. I do not 
want to check my daughters answers and tell her that one of her 
correct answers is incorrect simply because what was given to me is a 
wrong answer. Once again I apologize for such rude question, but I am 
desperate, and I ran out of all other options. I am also considering a 
big tip for those who'll work hard on these, do all (or most) of the 
questions, provide the correct answers and hopefully as soon as 
possible. 
  
Thank you once more. You are my last hope. 

1) What is the [(PO4)-3] in a solution made by
adding NaOH to a 0.20 M H3PO4 solution
until the pH = 11.00? (assume the volume
remains constant)

1. 0.072 M
2. 0.20 M
3. 0.15 M
4. 0.0034 M
5. 0.0069 M

2) Ka for HF is 7.2 * 10^-4 at 25deg Celcius.
What are the concentrations of H3O+ and
undissociated HF for a 0.05Msolution of HF?
(Solve full quadratic equation) The reaction is

	HF + H2O --> H3O+ + F- 

1. [H3O+] and [HF] = 5.7 * 10^-3 5.0 * 10^-2
2. [H3O+] and [HF] = 5.7 * 10^-3 3.9 * 10^-2
3. [H3O+] and [HF] = 2.7 * 10^-2 5.0 * 10^-2
4. [H3O+] and [HF] = 2.7 * 10^-2 2.3 * 10^-2
5. [H3O+] and [HF] = 5.7 * 10^-3 4.4 * 10^-2

3) The pH range of human blood plasma is 7.3 - 7.5.

After exercising, an athlete momentarily
reduces his blood pH. This reduction implies
a(n) _____________

1. basicity increase.
2. OH- concentration increase.
3. H+ concentration constant.
4. acidity increase.
5. H+ concentration decrease.
6. OH- concentration decrease.


4) A change in pH from 5 to 4 represents:

1. not enough information given
2. 10% less H+ ions in solution at pH 4 than
pH 5
3. 10% more H+ ions in solution at pH 4
than pH 5
4. 90% more H+ ions in solution at pH 4
than pH 5
5. 100% more H+ ions in solution at pH 4
than pH 5


5) HF is used to dissolve silicate rocks, HNO3 is
used to dissolve plants and HCl will dissolve
neither.

Which is considered a weak acid?

1. HNO3
2. HF
3. All are weak acids.... need to know Ka
4. None....all are strong acids values to determine the weakest.
5. HCl
Answer  
Subject: Re: chemistry questions part 4
Answered By: hibiscus-ga on 22 Oct 2003 20:06 PDT
 
Hello jwheel, 

I'm sorry your daughter is having so much trouble.  Of course it's
best that she understands what is going on in the course, but I often
find that having the right answers and then figuring out why they're
right is easier and less frustrating than working out an answer you
aren't sure of.

So, in order:

Question 1.  Answer: 4 (But I think you have a typo) 

From the Handbook of Chemistry and Physics the Ka of HPO4 is
2.2*10^-13(I'm assuming that this would be listed in your daughter's
textbook).

So 2.2*10^-13 = [H+] [PO4 3-]
                -------------
                  [HPO4 2]

              = [H+] [PO4 3-]
                ---------------
                0.20 - [PO4 3-]

Solve for [PO4 3-] gives 0.00430528, or just 0.0043.  I'm assuming
that either you or the creator of the question mistyped .0043 as
.0034.

Question 2.  Answer: 1

Just solve the quadratic of Ka = x^2 / (0.05 - x).  Since Ka is given
this is 7.2*10^-4 = x^2 / (0.05 - x)

Question 3.  Either 4 or 6.  This is an acidity increase, but by
definition an acidity increase means an OH- concentration decrease. 
So either answer should be correct.

Question 4. Answer: 2 (again, a typo?)

The pH scale is logarithmic, so a change from 5 to 4 is a change by
ten times, not ten percent.  At pH 4 there are 10% of the H+ ions of
pH 5, but NOT 10% LESS (which is what is written in the question, and
which would imply 90% of pH 5).

Question 5. Answer: 2

The information about what dissolves what is irrelevant.  HNO3 and HCl
are both strong acids.  HF is the only weak acid.

------------------

I hope this got to you in time to be of use.  I know that chemistry
can be a tricky thing to figure out, but with some luck and some
effort I'm sure your daughter can get it.

Hibiscus
Comments  
There are no comments at this time.

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy