

Subject:
algebra, factoring
Category: Miscellaneous Asked by: dj2965ga List Price: $2.50 
Posted:
16 Nov 2003 12:09 PST
Expires: 16 Dec 2003 12:09 PST Question ID: 276470 
How do you factor this equation x^2 + 16x + 64  100y^2 

Subject:
Re: algebra, factoring
Answered By: answerguruga on 16 Nov 2003 13:27 PST 
Hi dj2965ga, Although the comment by nauticoga was close, there is no benefit in placing 100y^2 in binomial factored form. The correct factorization of the expression you provided is actually: (x+8)^2 + (10y)^2 OR (x+8)*(x+8) + (10y)^2 Hope that helps :) answerguruga  


Subject:
Re: algebra, factoring
From: nauticoga on 16 Nov 2003 12:28 PST 
It's been more than 50 years since I took algebra, but thought I would give it a shot: (x+8)(x+8)  (10y+0)(10y+0) 
Subject:
Re: algebra, factoring
From: p2006ga on 16 Nov 2003 15:31 PST 
I believe that answerguru's answer is wrong, but only in a small way. It should be  (minus) (10y)^2, not + (10y)^2 because you had the 100y^2 term subtracted from the rest of the polynomial, (  100y^2). I believe that answerguru might have meant (x+8)^2 = (10y)^2 It could have been a typo since + and = are on the same key. Make sense? 
Subject:
Re: algebra, factoring
From: thegimp55ga on 18 Nov 2003 16:26 PST 
x^2 + 16x + 64  100y^2 = (x+8)^2  (10y)^2 / you reconize now a^2b^2 (a=x+8 and b=10y) =(x+8+10y).(x+810y) /which is equal to (a+b)(ab) the end. good luck with your studies! 
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