I suppose that this is really two questions, but I'm presenting them as one;

What is the weight, in U.S. lbs., of a one inch length of 3/4 inch
diameter rod of lead (11.35 gm/cc)?
What is the weight, in U.S lbs., of a one inch length of 3/4 inch
diameter rod of tungsten (19.3 gm/cc) ?

Hi,

Thank you for your question.

The following are conversions of the units we will use:

1 inch = 2.54 cm
3/4 inch = 1.905 cm
1 lbs = 453.5924 g

1-) For the first rod we have:

Volume of the rod = 1.905 x pi x 2.54 = 15.201 cc
                   diameter     length

Weight of the rod = 15.201 x 11.35 = 172.53 g
                    volume   density



Weight of the rod in lbs = 172.53/453.59 = 0.38 lbs


2-) For the second rod we have:

Volume of the rod = 15.201 cc

Weight of the rod = 15.201 x 19.3 = 292.38 g



Weight of the rod in lbs = 292.38/453.59 = 0.65 lbs


I hope this answers your question. If anything is unclear or you
require any clarifications, please do not hesitate to ask.

Thanks.
endo


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Clarification of Answer by endo-ga on 16 Dec 2003 10:38 PST

Ooops, thanks for that, sorry I made a very silly mistake. Racecar is right.

The volume of the rods are:

0.9525^2 x pi x 2.54 = 7.24 cc
  r^2    x pi x length


Weight of rod 1: 7.24 x 11.35 = 82.17 g

Weight of rod 1 in lbs: 82.17 / 453.59 = 0.18 lbs

Weight of rod 2: 7.24 x 19.3 = 139.72 g
Weight of rod 2 in lbs: 139.72 / 453.59 = 0.31 lbs

Sorry again for the confusion. Thanks to Racecar for pointing out the mistake.

Regards,
endo

This answer needs some fixin', endo-ga.

As I know you know, the area of a cylinder is not pi*diameter*length.

The correct volume is 7.240 cubic centimeters.

Ooops, for 'area of a cylinder', read 'volume of a cylinder'...

'long as I'm adding a second comment, the correct weights are .181 and .308 lb.

Thanks,

Steve

Ain;t weight = mass * gravity ?

A good website for conversion of various units is:
http://www.onlineconversion.com/

It converts most anything to anything.