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Subject:
Calculus I
Category: Reference, Education and News > Homework Help Asked by: cousinit-ga List Price: $4.50 |
Posted:
07 Jan 2004 07:18 PST
Expires: 06 Feb 2004 07:18 PST Question ID: 294004 |
lim (sqrt x - sqrt 3) / (x-3) Please show work. x->3 |
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Subject:
Re: Calculus I
Answered By: elmarto-ga on 07 Jan 2004 08:00 PST Rated: |
Hi cousinit! We can solve this problem by applying the following identity: (a+b)(a-b) = a^2 + ab - ab - b^2 = a^2 - b^2 where ^ means "to the power of". The limit you want to find is the following: lim (sqrt x - sqrt 3) x->3 ----------------- x-3 Now we can multiply both the numerator and the denominator by (sqrt x + sqrt 3) The idea is to get an (x-3) in the numerator that will cancel out with that same term in the denominator. So we have: lim (sqrt x - sqrt 3) (sqrt x + sqrt 3) x->3 -----------------.------------------- x - 3 (sqrt x + sqrt 3) Applying the identity I mentioned before, we have that: (sqrt x - sqrt 3)(sqrt x + sqrt 3) = x - 3 Therefore, we get: lim x - 3 x->3 -----------------.------------------- x - 3 (sqrt x + sqrt 3) which is the same as: lim 1 x->3 ----------------- (sqrt x + sqrt 3) Finally, since the function 1/(sqrt(x)+sqrt(3)) is continuous, we can just replace x=3 in order to get: lim 1 1 x->3 ----------------- = ---------- (sqrt x + sqrt 3) 2sqrt(3) I hope this helps! If you have any doubts regarding my answer, please don't hesitate to request a clarification before rating it. Otherwise I await your rating and final comments. Best wishes! elmarto |
cousinit-ga
rated this answer:
Thank you so much, especially for taking the time to explain the steps in words. |
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