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| Subject:
Calculus I
Category: Reference, Education and News > Homework Help Asked by: cousinit-ga List Price: $4.50 |
Posted:
07 Jan 2004 07:18 PST
Expires: 06 Feb 2004 07:18 PST Question ID: 294004 |
lim (sqrt x - sqrt 3) / (x-3) Please show work. x->3 |
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| Subject:
Re: Calculus I
Answered By: elmarto-ga on 07 Jan 2004 08:00 PST Rated: ![]() |
Hi cousinit!
We can solve this problem by applying the following identity:
(a+b)(a-b) = a^2 + ab - ab - b^2 = a^2 - b^2
where ^ means "to the power of".
The limit you want to find is the following:
lim (sqrt x - sqrt 3)
x->3 -----------------
x-3
Now we can multiply both the numerator and the denominator by
(sqrt x + sqrt 3)
The idea is to get an (x-3) in the numerator that will cancel out with
that same term in the denominator. So we have:
lim (sqrt x - sqrt 3) (sqrt x + sqrt 3)
x->3 -----------------.-------------------
x - 3 (sqrt x + sqrt 3)
Applying the identity I mentioned before, we have that:
(sqrt x - sqrt 3)(sqrt x + sqrt 3) = x - 3
Therefore, we get:
lim x - 3
x->3 -----------------.-------------------
x - 3 (sqrt x + sqrt 3)
which is the same as:
lim 1
x->3 -----------------
(sqrt x + sqrt 3)
Finally, since the function 1/(sqrt(x)+sqrt(3)) is continuous, we can
just replace x=3 in order to get:
lim 1 1
x->3 ----------------- = ----------
(sqrt x + sqrt 3) 2sqrt(3)
I hope this helps! If you have any doubts regarding my answer, please
don't hesitate to request a clarification before rating it. Otherwise
I await your rating and final comments.
Best wishes!
elmarto |
cousinit-ga
rated this answer:
Thank you so much, especially for taking the time to explain the steps in words. |
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