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Subject:
pH of a buffer
Category: Science > Chemistry Asked by: stef44-ga List Price: $2.00 |
Posted:
15 Mar 2004 13:11 PST
Expires: 14 Apr 2004 14:11 PDT Question ID: 317009 |
What's the pH of a buffer solution of formic acid HCOOH: K3=1.8 x 10(on -4) [HCOO]=0.5 M and [HCOOH]=0.15 M? Note: Henderson-Hasselback Equation is: pH=pK3 + log[A]/[HA] |
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There is no answer at this time. |
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Subject:
Re: pH of a buffer
From: stantheman-ga on 16 Mar 2004 16:34 PST |
HCOO = 0.5 HCOOH = 0.15 K3 = 1.8 x 10e(-4) pK3 = -log(K3) = 3.745 log(HCOO/HCOOH) = log(.5)/.15) = 0.523 pH = pK3 + log(HCOO/HCOOH) = 3.745 + 0.523 + 4.268 |
Subject:
Re: pH of a buffer
From: stef44-ga on 16 Mar 2004 20:45 PST |
thanks a lot for the answer. i mistyped Ka and pKa: K3 was suppose to be Ka and pK3 was suppose to be pKa. i see that you stuck with my 'acronyms' and went through calcualtions anyway. thanks again |
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