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Q: Astro Physic, Chemistry ( Answered 5 out of 5 stars,   0 Comments )
Question  
Subject: Astro Physic, Chemistry
Category: Science
Asked by: braggy-ga
List Price: $2.00
Posted: 29 Mar 2004 08:12 PST
Expires: 28 Apr 2004 09:12 PDT
Question ID: 321681
1. Which of the following demonstrates the greatest molecular activity?
A.  32?F
B.  -10?C
C.  264?K
D.  5?C
Answer  
Subject: Re: Astro Physic, Chemistry
Answered By: till-ga on 29 Mar 2004 08:51 PST
Rated:5 out of 5 stars
 
First I convert all temperatures to the same measure unit C
A. 32  F =  0     C
B.          -10    C
C. 264 K  = -9,15  C  
D.           5,0   C    

This can be done with:
( http://www.chemie.fu-berlin.de/chemistry/general/units_en.html#temp )

Now we see that D has the highest temperature. According to the Nernst
Theorem (also known as the Third Law of Thermodynamics) the molecular
activity is proportional to temperature, so D has the greatest
molecular activity:

"Nernst's theorem, sometimes referred to as the third law of
thermodynamics, states that the entropy of a system at zero absolute
temperature is a well-defined constant. This is due to the fact that a
system at zero temperature exists in its ground state, so that its
entropy is determined by the degeneracy of the ground state. Many
systems, such as crystal lattices, have a unique ground state, and
therefore have zero entropy at at absolute zero (since ln(1) = 0)."
from:
Third Law of Thermodynamics
( http://www.fact-index.com/t/th/third_law_of_thermodynamics.html )


I hope this helps to solve your problem.

till-ga


Search strategy:

Unit Conversion:
( ://www.google.de/search?sourceid=navclient&hl=de&ie=UTF-8&oe=UTF-8&q=temperature+conversion
)

Third Law

( ://www.google.de/search?sourceid=navclient&hl=de&ie=UTF-8&oe=UTF-8&q=nernst+theorem
)
braggy-ga rated this answer:5 out of 5 stars and gave an additional tip of: $1.00

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