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 Subject: Astro Physic, Chemistry Category: Science Asked by: braggy-ga List Price: \$2.00 Posted: 29 Mar 2004 08:12 PST Expires: 28 Apr 2004 09:12 PDT Question ID: 321681
 ```1. Which of the following demonstrates the greatest molecular activity? A. 32?F B. -10?C C. 264?K D. 5?C```
 ```First I convert all temperatures to the same measure unit °C A. 32 ° F = 0 ° C B. -10 ° C C. 264 K = -9,15 ° C D. 5,0 ° C This can be done with: ( http://www.chemie.fu-berlin.de/chemistry/general/units_en.html#temp ) Now we see that D has the highest temperature. According to the Nernst Theorem (also known as the Third Law of Thermodynamics) the molecular activity is proportional to temperature, so D has the greatest molecular activity: "Nernst's theorem, sometimes referred to as the third law of thermodynamics, states that the entropy of a system at zero absolute temperature is a well-defined constant. This is due to the fact that a system at zero temperature exists in its ground state, so that its entropy is determined by the degeneracy of the ground state. Many systems, such as crystal lattices, have a unique ground state, and therefore have zero entropy at at absolute zero (since ln(1) = 0)." from: Third Law of Thermodynamics ( http://www.fact-index.com/t/th/third_law_of_thermodynamics.html ) I hope this helps to solve your problem. till-ga Search strategy: Unit Conversion: ( ://www.google.de/search?sourceid=navclient&hl=de&ie=UTF-8&oe=UTF-8&q=temperature+conversion ) Third Law ( ://www.google.de/search?sourceid=navclient&hl=de&ie=UTF-8&oe=UTF-8&q=nernst+theorem )```