Google Answers Logo
View Question
 
Q: Astro Physics ( Answered,   1 Comment )
Question  
Subject: Astro Physics
Category: Science > Astronomy
Asked by: braggy-ga
List Price: $3.50
Posted: 17 Apr 2004 13:09 PDT
Expires: 17 May 2004 13:09 PDT
Question ID: 331811
A substance has a 1/2 life of 12 days.  At day 0 you have 28grams of
the material.  How much will be left. after 36 days pass?

Please explain how you reached your answer Be explicit.
Answer  
Subject: Re: Astro Physics
Answered By: eiffel-ga on 18 Apr 2004 06:47 PDT
 
Hi braggy,

Because 36 days is an integer multiple of the half-life, we can work
out the answer by taking one half-life period at a time:

   At day  0, we have 28 grams
   At day 12, we have half of this (14 grams)
   At day 24, we have half again (7 grams)
   At day 36, we have half again (3.5 grams)

Alternatively, we can use a general formula for exponential decay
which will allow us to work out the amount of substance remaining
after any number of days.

The formula for exponential decay is

   s = s0 * e ^ (k * t)

where

   s is the amount of the substance at any time t
   s0 is the amount of the substance at day 0
   e is the base of the natural logarithms (2.718281828459...)
   k is some constant showing how quickly the substance decays
   t is the time since day 0
   * represents multiplication
   ^ represents exponentiation

First we must find the value of 'k' for this substance. What we do
know is that after 12 days, half of the substance remains (14 grams).
We plug these values into the formula:

   14 = 28 * e ^ (k * 12)

Divide both sides by 28:

   0.5 = e ^ (k * 12)

Take the natural logarithm of both sides:

   ln 0.5 = ln(e ^ (k * 12))

Cancel the 'ln' and the exponentiation on the right-hand-side, which
we can do because e^(ln x)=x for any x:

   ln 0.5 = k * 12

Solve for 'k':

   k = (ln 0.5)/12 = -0.057762265046662

Now, having found 'k', we can use our original formula to find the
amount of substance remaining after 36 days:

   s = 28 * e ^ (-0.057762265046662 * 36)

     = 3.5 grams

A worked example in more detail can be found here:
http://math.usask.ca/emr/examples/expdeceg.html

If you don't understand any part of my explanation above, please ask
for more details by requesting a clarification.


Google Search Strategy:

"exponential decay" formula
://www.google.com/search?q=%22exponential+decay%22+formula


Regards,
eiffel-ga
Comments  
Subject: Re: Astro Physics
From: corwin02-ga on 17 Apr 2004 14:05 PDT
 
Ending amount = (beginning amount/2N) where 

N= elapsed time/halflife 

or 

N= number of half lives


ergo 3.5 gr or 12.5 percent 

28 <12> = 14
14 <12>=  7
7 <12> = 3.5

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy