Google Answers Logo
View Question
 
Q: Finance Problem (Financial calc. may be necessary) ( No Answer,   4 Comments )
Question  
Subject: Finance Problem (Financial calc. may be necessary)
Category: Business and Money > Finance
Asked by: jax26-ga
List Price: $2.00
Posted: 17 Apr 2004 16:07 PDT
Expires: 19 Apr 2004 07:57 PDT
Question ID: 331878
Rachel wants to take a trip to England in 3 years, and she has started
a savings account today to pay for the trip.  Today (8/1/02) she made
an initial deposit of $1,000.  Her plan is to add $2,000 to the
account one year from now (8/1/03) and another $3,000 to the account
two years from now (8/1/04).  The account has a nominal interest rate
of 7%, but the interest is compounded quarterly.  How much will Rachel
have in the account 3 years from today (8/1/05)?
     Please note:  The solution is somewhere in between:  $6,500 and $7,000.
Answer  
There is no answer at this time.

Comments  
Subject: Re: Finance Problem (Financial calc. may be necessary)
From: jiiins-ga on 18 Apr 2004 06:35 PDT
 
Answer:

6,508.18
Subject: Re: Finance Problem (Financial calc. may be necessary)
From: jax26-ga on 18 Apr 2004 19:38 PDT
 
I don't believe that to be the answer; I have narrowed down the answer
to be between  $6,700 and $6,900.  (I used N = 12 and periodic rate =
7/4 = 1.75%
Subject: Re: Finance Problem (Financial calc. may be necessary)
From: aht-ga on 18 Apr 2004 22:41 PDT
 
jax26-ga:

As an academic exercise, the easiest way to 'see' this problem is to
use a spreadsheet (ie. Excel).

Set up 13 columns, each with the starting date of a quarter; ie,
Column A starts with Aug/01/2002, Col B is Nov/01/2002, etc, to Col M
which is Aug/01/05. That's row 1.

In Cell A2, put 1000. In Cell B2, put "=A2*1.0175" to calculate the
value after one quarter... then drag the formula across the remaining
cells in the row so that Cell M2 has "=L2*1.0175" in it. M2 is the
value of the original $1000 investment at the end of 3 complete years.

In Cell E3 (ie. Aug/01/2003), put 2000. F3 is going to be
"=E3*1.0175", and again drag to M3 which will be "=L3*1.0175". That's
the value of the $2000 after two years (Aug/01/2003 to Aug/01/2005).

In Cell I4, which is Aug/01/2004, put 3000; J4, "=I4*1.0175", etc. to
M4 "=L4*1.0175". You guessed it, this is the value of the $3000 after
one full year of interest.

Add up the three values in M2, M3, M4, and you have your total: $6744.78.

Now, you can figure out how to write this as a formula!

Hope this helps, 

aht-ga
Google Answers Researcher
Subject: Re: Finance Problem (Financial calc. may be necessary)
From: jax26-ga on 19 Apr 2004 07:54 PDT
 
Thank you.  My answer matches the answer you calculated.  

//S

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy