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Subject:
Finance Problem (Financial calc. may be necessary)
Category: Business and Money > Finance Asked by: jax26-ga List Price: $2.00 |
Posted:
17 Apr 2004 16:07 PDT
Expires: 19 Apr 2004 07:57 PDT Question ID: 331878 |
Rachel wants to take a trip to England in 3 years, and she has started a savings account today to pay for the trip. Today (8/1/02) she made an initial deposit of $1,000. Her plan is to add $2,000 to the account one year from now (8/1/03) and another $3,000 to the account two years from now (8/1/04). The account has a nominal interest rate of 7%, but the interest is compounded quarterly. How much will Rachel have in the account 3 years from today (8/1/05)? Please note: The solution is somewhere in between: $6,500 and $7,000. |
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There is no answer at this time. |
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Subject:
Re: Finance Problem (Financial calc. may be necessary)
From: jiiins-ga on 18 Apr 2004 06:35 PDT |
Answer: 6,508.18 |
Subject:
Re: Finance Problem (Financial calc. may be necessary)
From: jax26-ga on 18 Apr 2004 19:38 PDT |
I don't believe that to be the answer; I have narrowed down the answer to be between $6,700 and $6,900. (I used N = 12 and periodic rate = 7/4 = 1.75% |
Subject:
Re: Finance Problem (Financial calc. may be necessary)
From: aht-ga on 18 Apr 2004 22:41 PDT |
jax26-ga: As an academic exercise, the easiest way to 'see' this problem is to use a spreadsheet (ie. Excel). Set up 13 columns, each with the starting date of a quarter; ie, Column A starts with Aug/01/2002, Col B is Nov/01/2002, etc, to Col M which is Aug/01/05. That's row 1. In Cell A2, put 1000. In Cell B2, put "=A2*1.0175" to calculate the value after one quarter... then drag the formula across the remaining cells in the row so that Cell M2 has "=L2*1.0175" in it. M2 is the value of the original $1000 investment at the end of 3 complete years. In Cell E3 (ie. Aug/01/2003), put 2000. F3 is going to be "=E3*1.0175", and again drag to M3 which will be "=L3*1.0175". That's the value of the $2000 after two years (Aug/01/2003 to Aug/01/2005). In Cell I4, which is Aug/01/2004, put 3000; J4, "=I4*1.0175", etc. to M4 "=L4*1.0175". You guessed it, this is the value of the $3000 after one full year of interest. Add up the three values in M2, M3, M4, and you have your total: $6744.78. Now, you can figure out how to write this as a formula! Hope this helps, aht-ga Google Answers Researcher |
Subject:
Re: Finance Problem (Financial calc. may be necessary)
From: jax26-ga on 19 Apr 2004 07:54 PDT |
Thank you. My answer matches the answer you calculated. //S |
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