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Subject:
Calculus Problem
Category: Science > Math Asked by: gyrocopter-ga List Price: $5.00 |
Posted:
02 May 2004 23:52 PDT
Expires: 01 Jun 2004 23:52 PDT Question ID: 340148 |
If log(9!) = 5.5598, what is the value of log(10!)? (show work) |
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Subject:
Re: Calculus Problem
Answered By: livioflores-ga on 03 May 2004 00:33 PDT Rated: |
Hi gyrocopter!! I will use the following property: log(a*b) = log(a) + log(b) 9! = 9*8*7*6*5*4*3*2*1 , then log(9!) = log(9)+log(8)+...+log(1) = 5.5598 10! = 10*9*8*7*6*5*4*3*2*1 = 10*9! , then log(10!) = log(10) + log(9!) = = 1 + 5.5598 = = 6.5598 I hope this helps. Feel free to request for a clarification if it needed. Regards. livioflores-ga |
gyrocopter-ga rated this answer: and gave an additional tip of: $1.00 |
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