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Q: Calculus Problem ( Answered 5 out of 5 stars,   0 Comments )
Question  
Subject: Calculus Problem
Category: Science > Math
Asked by: gyrocopter-ga
List Price: $5.00
Posted: 02 May 2004 23:52 PDT
Expires: 01 Jun 2004 23:52 PDT
Question ID: 340148
If log(9!) = 5.5598, what is the value of log(10!)? (show work)
Answer  
Subject: Re: Calculus Problem
Answered By: livioflores-ga on 03 May 2004 00:33 PDT
Rated:5 out of 5 stars
 
Hi gyrocopter!!


I will use the following property:

log(a*b) = log(a) + log(b)

9! = 9*8*7*6*5*4*3*2*1 , 

then

log(9!) = log(9)+log(8)+...+log(1) = 5.5598


10! = 10*9*8*7*6*5*4*3*2*1 = 10*9! , 

then

log(10!) = log(10) + log(9!) = 
         = 1 + 5.5598 =
         = 6.5598


I hope this helps. Feel free to request for a clarification if it needed.

Regards.
livioflores-ga
gyrocopter-ga rated this answer:5 out of 5 stars and gave an additional tip of: $1.00

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