If -2< x <2use binomial theorem to expand
   1
-------
(2 + x)     as far as the third term

1/(x+2) = (x+2)^(-1) = sum[(-1Ck)(x^k)(2^(-1-k))]

use (-1Ck) = (-1)^k (kCk) = (-1)^k:

1/(x+2) = sum[(-1)^k (x^k)(2^(-1-k))]

so, by expanding:

1/(x+2) = 1/2 - x/4 + x^2/8 - x^3/16  (and so forth...)

1/x - 2/x^2 + 4/x^3

scratch that

Hint:  U substitution where U = X + 2, U from 0 to 4, 1/U

Not difficult in any way.  Do yourself a favor and learn what you are studying.  :)

Thanks for the hints and answers. leoj, difficult after ten years of forgetting! ;)