Two ranchers sold a herd of cattle and received and received as many
dollars for each animal as there were cattle in the herd. (If there
were two animals, they received two dollars for each one; if three, 3
dollars for each one; etc. We're told they started with no more than
20 cattle). With the money, they bought as many sheep as they could at
10 dollars a head, and a goat with the remainder(less ten dollars).
Finally, they divided the animals between them. There was, however, an
odd number of sheep. So the one rancher took the extra sheep, and the
other the goat. The rancher who got the goat was given his friend's
new pocketknife as compensation. If this was an equal division, what
was the value of the pocketknife. (Hint: externalize; list the
squares).

Answer is 4$

Thanks- could you please show your calculations.

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