Dimples and freckles are both autosomal dominant phenotypes. If a man
who is heterozygous for both these genes marries a woman who is
heterozygous for dimples but homozygous recessive for freckles gene,
then what is the probability that they will have a child with dimples
and freckles?
a. 1/16 
b. 2/16 
c. 3/16 
d. 6/16 OR 3/8 
e. 9/16

d. 6/16 or 3/8

Crossing two heterozygous individuals produces a dominant phenotype
3/4 of the time (a). Crossing a homozygous recessive with a
heterozygous produces a dominant phenotype 2/4 or 1/2 of the time.
Thus, to have both traits, simply multiply the two, 2/4 * 3/4 = 6/16.
        r  R
     +------
   r | rr rR
a) R | rR RR = 3/4

        r  R
     +------
   r | rr rR
b) r | rr RR = 2/4

I hope this helps, don't forget to rate. Feel free to ask for clarification.

Cheers,
Tox-ga

As the question may appear it looks like I am asking someone to do my
homework for me but the truth is that these questions are from a test
that I failed and I am now seeking other ways to better understand
these concepts.  I have tried to seek other help with my professor but
she has not been responsive.