|
|
Subject:
Dimples and freckles are both autosomal dominant phenotypes. If a man who is het
Category: Science > Biology Asked by: operator-ga List Price: $2.00 |
Posted:
14 Jun 2004 14:16 PDT
Expires: 14 Jul 2004 14:16 PDT Question ID: 361050 |
The color of chickens is determined by gene B, such that BB= black, Bb = gray, and bb = white. A second gene R controls comb shape, with dominant rose and recessive single comb. If a white single-combed chicken is mated with a gray chicken that is heterozygous for rose comb, what fraction of the offspring will be gray with rose comb? a. 1/4 b. 9/16 c. 1/8 d. 3/8 e. 1/16 |
|
Subject:
Re: Dimples and freckles are both autosomal dominant phenotypes. If a man who is het
Answered By: librariankt-ga on 15 Jun 2004 12:33 PDT |
Hi operator, The answer is a: 1/4 Look at it this way: you have one chicken that is bbrr (white, single comb) and another chicken that is BbRr (grey, heterozygous rose comb). Half of the chickens will end up grey (Bb), with half of those being rose combed (Rr). This is because a heterozygous/homozygous mating ALWAYS results in half heterozygous, half homozygous for any ONE set of alleles - so if you've got two sets you'll have 1/4th hetero for both, 1/4th hetero for one, homo for the other, 1/4th reversed of that, and 1/4th homo for both. Let me know if that's confusing. I understand you're trying to understand why you didn't get these right on a test. Please let me know if my explanation is unclear and I'll approach it from a different angle. Librariankt | |
|
|
There are no comments at this time. |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |