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PROBLEM #1
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Jo has zero books.
If the first statement (Jo has more than 999 books) were true, then
the third statement (Jo has at least one book) would be true. This
cannot be, since there can be only one true statement.
If the third statement (Jo has at least one book) were true, the
second statement (Jo has fewer than 1000 books) would also be true.
This cannot be, since there can be only one true statement.
Thus we are left with the second statement (Jo has fewer than 1000
books), which can be true only if Jo has zero books.
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PROBLEM #2
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You can do this with two cuts: cut the fourth link and the tenth link.
Your 21-link chain now looks like this, with 0 representing intact
links, and C representing cut links:
000 C 00000 C 00000000000
Here's how you can arrange your payments to the innkeeper:
On the first day. give the innkeeper one of the cut links.
On the second day, let the innkeeper keep the cut link, and give him
the other cut link, so that he now holds the two cut links.
On the third day, take back both of the cut links, and give the
innkeeper the first segment of the chain, which contains three links.
On the fourth day, let the innkeeper keep the 3-link segment, and add
to it one of the cut links.
On the fifth day, take back everything from the innkeeper and
substitute the 5-link segment of the chain.
On the sixth day, let the innkeeper keep the 5-link segment, and add
one of the cut links.
On the seventh day, let the innkeeper keep the 5-link segment and the
cut link, and give him the other cut link.
On the eighth day, let the innkeeper keep the 5-link segment; swap the
3-link segment for the two cut links.
On the ninth day, let the innkeeper keep the 5-link and 3-link
segments, and add one cut link.
On the tenth day, let the innkeeper keep the 5-link and 3-link
segments and the cut link, and add the other cut link.
On the eleventh day, take everything back and give the innkeeper the
11-link segment.
On the twelfth day, let the innkeeper keep the 11-link segment, and
add one cut link.
On the thirteenth day, let the innkeeper keep the 11-link segment and
the cut lnk, and add the other cut link.
On the fourteenth day, let the innkeeper keep the 11-link segment;
take back both cut links, and give the innkeeper the 3-link segment.
On the fifteenth day, let the innkeeper keep the 11-link segment and
the 3-link segment, and add one cut link.
On the sixteenth day, let the innkeeper keep the 11-link segment. Take
back the 3-link segment and the cut link, and give the innkeeper the
5-link segment.
On the seventeeth day, let the innkeeper keep the 11-link segment and
the 5-link segment, and give the innkeeper one cut link.
On the eighteenth day, let the innkeeper keep the 11-link segment, the
5-link segment, and the cut link, and give him the other cut link.
On the nineteenth day, let the innkeeper keep the 11-link segment and
the five-link segment; take back both cut links, and give him the
3-link segment.
On the twentieth day, let the innkeeper keep the 11-link segment, the
five-link segment, and the 3-link segment, and add one cut link.
On the twenty-first day, let the innkeeper keep the 11-link segment,
the five-link segment, the 3-link segment, and the cut link; add the
other cut link. The innkeeper now has the entire chain.
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PROBLEM #3
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2 boys go across.
1 boy comes back.
1 man goes across.
The other boy comes back.
Repeat this till all 9 of the men have gone across. Then both boys
come across together, and everyone has crossed the river.
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If anything is unclear, or if I have misunderstood any of these
puzzles, please request clarification; I'll gladly offer further
assistance before you rate my answer.
Best regards,
pinkfreud |