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Q: empirical formulas ( No Answer,   3 Comments )
Question  
Subject: empirical formulas
Category: Health > Medicine
Asked by: charlie248-ga
List Price: $2.00
Posted: 17 Jul 2004 17:55 PDT
Expires: 16 Aug 2004 17:55 PDT
Question ID: 375567
I need to know the difference between the empirical formulas for
oxycocone and heroin, giving also the crystaline struture of both,
noting the similarities and differences. This is in reguards to the
pain management program my girlfriend is on.
Answer  
There is no answer at this time.

Comments  
Subject: Re: empirical formulas
From: purkinje-ga on 17 Jul 2004 19:09 PDT
 
The empirical formula is the same as the actual formula:
Oxycodone - C18O3N
Heroine   - C21O5N

The two are the same in structure except for oxycodone has a methoxy
group at C3, and a ketone at C6, while heroin has a double methoxy
group (-OCOCH3) at positions 3 and 6.

The crystaline structure refers to how those molecules crystallize
together-- are you asking what crystalline shapes they will assume?
There's probably not a good answer for that. If you're trying to
distinguish between heroine and an oxycontin pill, that won't really
help you anyway since oxycontin has many excipients. Well, hope that
helps!
Subject: Re: empirical formulas
From: purkinje-ga on 17 Jul 2004 19:30 PDT
 
Sorry, I totally forgot to count the hydrogens! The CORRECT formulas
(I also forgot to count an -OH group on oxycodone) are:
C18O4NH29
C21O5NH29
Subject: Re: empirical formulas
From: arsenic-ga on 18 Jul 2004 13:13 PDT
 
Heroin gives orthorhombic plates or tablets when crystallized from
ethyl acetate, oxycodone gives long rods from alcohol. (The tautomeric
form of oxycodone gives from alcohol strongly refringent scales)

Source: The Merck Index 12th ed.

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