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Q: Lateral area of pyramid ( Answered ,   0 Comments )
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 Subject: Lateral area of pyramid Category: Science > Math Asked by: torrey2-ga List Price: \$2.00 Posted: 20 Jul 2004 17:26 PDT Expires: 19 Aug 2004 17:26 PDT Question ID: 376900
 ```A pyramid has a slant height of 6 meters. If its base is a regular octagon with sides that measure 4 meters, find the lateral area of the pyramid.```
 ```Hi there, The first thing you need to do is find the height of one of faces that make up the pyramid. Each face is a triangle, so to find its height you need to take the 4m base of the triangle and bisect it giving you a point 2m from each side. From that point you can draw a line up to the apex of the pyramid. Once you have this line, you can use the Pythagorean theorem (a^2+b^2=c^2) to find the height of the triangle. h^2=6^2-2^2 h^2=36-4 h^2=32 h=sqrt32 Now that you have the height of one of the faces you can use the formula for the area of a triangle (base*height)/2 to find the area of one of the faces of the pyramid. Multiply the area of the face by 8 and you will get the lateral area of the pyramid. area=[(4*sqrt32)/2]*8 =90.50966799 I hope this answers your question! If you have any questions or are unclear about anything please feel free to ask for clarification. Regards, Deadlychiapet```