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Subject:
Zeppelin Helium
Category: Science > Chemistry Asked by: comogreg-ga List Price: $2.00 |
Posted:
08 Aug 2004 09:56 PDT
Expires: 07 Sep 2004 09:56 PDT Question ID: 385038 |
What volume of helium, at sea level pressure, and at 60 degrees F, would lift one pound of weight? | |
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There is no answer at this time. |
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Subject:
Re: Zeppelin Helium
From: crythias-ga on 08 Aug 2004 18:58 PDT |
According to another Google Answer, about 15.886524 cubic feet. http://answers.google.com/answers/threadview?id=17938 Not certain how much of a role temperature plays, considering it's pretty much all about displacement and gravity. (Read: Nobody really considers the temperature of the water when asking how much water the ship displaces) Neither do I believe distance much matters. Consider nobody asks how much lead has to weigh to sink 1000 feet in water. And yes, they are the same concept. |
Subject:
Re: Zeppelin Helium
From: crythias-ga on 08 Aug 2004 19:08 PDT |
Let me rethink that. It does make a difference, doesn't it? The equivalence is lead pulling a balloon underwater 1000 feet, but again, not really. As you go down, pressure increases around the balloon. Eventually, the pressure should either equivalently buoy the balloon, or the pressure would pop the balloon. Pressure decreases about the helium balloon. I know I've given part of the answer, but I wonder if the other part is that helium escapes the balloon as the balloon expands. Still, I doubt that there is a correlation in volume versus height, unless it's a functional issue with the balloon. |
Subject:
Re: Zeppelin Helium
From: touf-ga on 09 Aug 2004 17:23 PDT |
Height absolutely makes a difference, because as you increase height above sea level, atmospheric pressure decreases. Therefore, the number of air molecules physically present decreases. Therefore, the air density decreases. (Same reason why it's harder to breathe atop Mt Everst than in Hawaii -- there's less air!) Since the whole reason helium lifts has to do with buoyancy force caused by varying densities, then as the delta-density decreases to zero, lifting power also decreases to zero. Assuming your two gases (air and helium) are at the same temperature, the effects of temperature are cancelled out. You can use the equation PV = nRT, where P is your pressure, V = volume, n = number of moles of gas, R = universal gas constant, T = temperature in Kelvin. |
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