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There are 119 ways to choose two, three, four, five, or six magazines
from seven in such a way that order is unimportant.
In order to perform this calculation, we use the mathematical idea of
combinations. The question you ask is basically akin to asking, "If
there are seven available pizza toppings, how many pizzas can we order
with anywhere from two to six toppings?"
To give a quick example of a specific one of the cases we're looking
at: let's say we are putting three out of seven toppings on our pizza.
(This is denoted "7 choose 3" or "7C3" mathematically.) Then there are
seven choices for the first topping, six choices for the second, and
five choices for the third. This seems to indicate that there are
7*6*5=210 possible pizzas we can make. BUT, it doesn't matter what
order we put the toppings on--if we put on onions, then mushrooms,
then peppers, this is the same pizza that we have if we put on
mushrooms, then peppers, then onions. There are -six- different orders
that we could have applied the three chosen toppings, all of which
make the same pizza in the end, so our original guess of 210 different
pizzas is too great by a factor of six. So the actual number of
three-topping pizzas is 210/6=35.
For more information on mathematical combinations and how to calculate them, see
Here are the number of available combinations of 2, 3, 4, 5, and 6
magazines from seven:
Choose two magazines from seven: 21 ways
Three from seven: 35 ways
Four from seven: 35 ways
Five from seven: 21 ways
Six from seven: 7 ways
For a total of 119 ways to choose 2, 3, 4, 5, or 6 magazines from seven.
Additionally, there are seven ways to choose just one magazine, one
way to choose all seven magazines, and one way to choose no magazines
I have written out a list of all the possible combinations, but it is
quite long, so I will point you to a text file:
I hope this answers your question! If you have any further questions,
or if you cannot access the text file, please request a clarification
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