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Subject:
Chemistry: Spectophotometric analysis
Category: Science > Chemistry Asked by: uncross-ga List Price: $30.00 |
Posted:
04 Sep 2004 14:18 PDT
Expires: 04 Oct 2004 14:18 PDT Question ID: 396874 |
Show me how to calculate these? And the answers?: What are the bromophenol blue concentrations in a mixture of the following reagents measurements? 0.10M Citrate Buffer pH = 2.4 (5.00mL) and 1.5E-04M Bromophenol Blue (0.00mL) 0.10M Citrate Buffer pH = 2.4 (4.50mL) and 1.5E-04M Bromophenol Blue (0.50mL) 0.10M Citrate Buffer pH = 2.4 (4.00mL) and 1.5E-04M Bromophenol Blue (1.00mL) 0.10M Citrate Buffer pH = 2.4 (3.00mL) and 1.5E-04M Bromophenol Blue (2.00mL) 0.10M Citrate Buffer pH = 2.4 (2.00mL) and 1.5E-04M Bromophenol Blue (3.00mL) 0.10M Citrate Buffer pH = 2.4 (1.00mL) and 1.5E-04M Bromophenol Blue (4.00mL) 0.10M Citrate Buffer pH = 2.4 (0.00mL) and 1.5E-04M Bromophenol Blue (5.00mL) |
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There is no answer at this time. |
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Subject:
Re: Chemistry: Spectophotometric analysis
From: nanoalchemist-ga on 07 Sep 2004 10:08 PDT |
Looks like you're doing a standard addition/ calibration curve. The easy way to calculate this, since you're already in M is to use M1V1 = M2V2 where the Ms are Molarities, and V volumes Rearange to get M2 M2= M1V1 / V2 The volume units will cancel leaving you units of M, which you want. Fortunatly for you, V2 is a constant 5 ml, and M1 is also constant (1.5 E-4 M), you then have M2 = (1.4 E-4 M)*V1 / 5 ml Thus, for your examples 1) M2 = (1.4 E-4 M)*0 ml / 5 ml = 0 M 2) M2 = (1.4 E-4 M)*0.5 ml / 5 ml = 1.4 E-5 M . . (etc) . 7) M2 = (1.4 E-4 M)*5 ml / 5 ml = 1.4 E-4 M |
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