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Subject:
Question in Optics. plano-convex
Category: Science > Physics Asked by: al3in-ga List Price: $5.00 |
Posted:
07 Sep 2004 06:09 PDT
Expires: 07 Oct 2004 06:09 PDT Question ID: 397840 |
Question # 16 from chapter 3 in "Introduction to Optics" by Pedrotti, second edition. A plano-convex lens having a focal length of 25.0 cm is to be made with glass of refractive index 1.520. Calculate the radius of curvature of the convex side of this lens |
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Subject:
Re: Question in Optics. plano-convex
Answered By: redhoss-ga on 07 Sep 2004 07:17 PDT Rated: |
Hello again al3in, I decided to learn a little more about optics. http://cvu.strath.ac.uk/courseware/msc/jbaggot/lenses/lenses.html This is a basic equation used to calculate the focal length of a lens given the radius of curvature of the lens and the refractive index of the lens relative to the medium. It is only an approximation and works best for thin lenses. 1/f = (n-1)(1/R1 - 1/R2) where n is the refractive index of the lens For a plano-convex lens R2 is flat. Therefore, 1/R2 is 1/infinity or zero. The formula then becomes: 1/f = (n-1)(1/R1) Plugging in your values: 1/25cm = (1.520 - 1)(1/R1) 1/25cm = 0.52 / R1 R1 = 25cm x 0.52 = 13cm Hope this makes sense to you, Redhoss |
al3in-ga
rated this answer:
Perfect answer. Thanks alot. |
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