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Subject:
Percent Difference
Category: Science > Math Asked by: massradius-ga List Price: $4.50 |
Posted:
14 Sep 2004 14:20 PDT
Expires: 14 Oct 2004 14:20 PDT Question ID: 401178 |
My company calculates absolute percent error the following way: (ABS(FCST-SALES)/FCST) There are two absolute error calculations. One is based on the customers orignal forecast vs. what they bought and the other is based on a system created forecast (linear demand based on history) vs. what they bought. At the end of each month the system spits out the two errors. My issue is if I only have the percent error for each of the forecasts how would I go about calculating percent difference....I thought it was just a simple subtraction (i.e. one minus the other) but someone else is actually calculating percent difference...who is right and why? | |
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Subject:
Re: Percent Difference
Answered By: efn-ga on 20 Sep 2004 21:27 PDT |
Hi massradius, Thanks for accepting my tentative answer, which appears below as a comment. Here I will address your request for clarification. The formula for what I called the scientific method of calculating percent difference in a programming or spreadsheet style of notation would be ABS(A - B) / ((A + B) / 2) In the first example in my comment, the input values are 9900 and 50, so applying this formula gives ABS(9900 - 50) / ((9900 + 50) / 2) = 9850 / 4975 = 1.9798994... This method would be appropriate for measuring how close together two approximate measurements of the same quantity are. In the absence of any information about what the value being measured really is, this formula just assumes that it is right in the middle of the two measurements. For example, if you have two thermometers side by side and one reads 99 degrees while the other reads 101 degrees, the formula says the true temperature is right in the middle, 100 degrees, and so the percent difference is 2%. Similarly, if the thermometers read 90 and 110, the percent difference would be 20%. So this method doesn't really make sense in your situation, since the two absolute error percentages you have are not really different approximations of some common underlying absolute error reality. In response to your second question, yes, if you had the raw data, you could come up with a meaningful percent difference, at least in a sense. If you calculated error percentages using the actual sales instead of the forecasts as the denominator, then both would have the same denominator and it would be meaningful to subtract one from the other. In fact, you wouldn't even need all the raw data. If you just had absolute error percentages like you have now, except calculated with the actual sales as the denominator, it would be meaningful to subtract one from the other. I have to qualify that, though. That might be considered a percentage point difference rather than a true percent difference. It's a problem like when something increases from 5% to 10% of some other quantity. Did it increase 10 - 5 = 5%? Or did it increase 100% because it doubled? Some might use whichever interpretation supports their case--the same change might be described as "a meager 5%" or "a whopping 100%," depending on the speaker's agenda. A careful writer might describe the increase as "5 percentage points" to distinguish it from the more ambiguous "5 percent." Similarly, a percent difference between two numbers usually has one of the numbers as the denominator, e.g., the percent difference between 90 and 100 is either 10% or 11.111...%, depending on which one you choose as the denominator. But if you subtract error percentages as I suggested, the denominator is not either of the percentage numbers, it's the actual sales. So the difference is not exactly a percent difference in the usual sense. However, I think it would provide a meaningful measure of the variance between the forecasts. There are probably more sophisticated statistical methods of comparing the forecasts, but they are beyond my expertise, and, I hope, beyond the scope of this question. I am fairly confident of my original assertion that you can't get a meaningful percent difference with the inputs you have. --efn |
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Subject:
Re: Percent Difference
From: efn-ga on 19 Sep 2004 02:07 PDT |
Hi massradius, I'm not quite confident enough of my opinion to post it as an answer, so I'm posting it as a comment. If you say it's worth the price you have offered for the question, I'll be happy to post it as the answer. I don't think a meaningful percent difference can be calculated from the inputs you have. The problem is that the inputs are the values of fractions with different denominators, so they measure different units, and the denominators are unknown, so you can't convert them to a common denominator. I'll try to illustrate with a few extreme examples. In this discussion, the typical percent difference method is the one used by your colleague, (a - b)/a. We don't have any particular reason to choose APEC or APES as the denominator (at least, I don't), so I will calculate it both ways. The scientific percent difference method is the one I mentioned in one of my Requests for Clarification, the absolute value of the difference divided by the mean. Let's say FC = 1, FS = 200, and AS = 100. Then APEC = 9900% and APES = 50%. By the subtraction method, the percent difference is 9850%. By the typical percent difference method, the difference is either about 99% or 19700%, depending on what you choose as the denominator. By the scientific percent difference method, the difference is about 198%. Then let's say the next month FC = 5 and FS and AS are the same. APEC then is 1900%. By the subtraction method, the percent difference has decreased from 9900% to 1900%. By the typical percent difference method, the difference either changed from 99% to about 97% or from 19700% to 3700%. By the scientific percent difference method, the difference decreased from 198% to about 190%. Now consider a month where FC = 100 and FS and AS are again the same. APEC then is 0. By the subtraction method, the difference is 50%. By the typical percent difference method, the difference is either 1 or incalculable. By the scientific percent difference method, the percent difference is 200%. These examples show that all the methods are flawed. The subtraction method generates a huge change in the percent difference when FC makes a relatively trivial change from 1 to 5. With the typical percent difference method, if the input you choose as the denominator is small, it can generate a huge percent difference, even if the inputs are not very far apart. And the scientific percent difference method generated almost the same percent difference in the first case, when FC was 1% of AS, and the third case, where FC was exactly equal to AS. If you want to compare the accuracy of the forecasts, you can look at which of the absolute percent errors is bigger. But I don't think you can calculate the difference between them in any useful way. I can't prove this, though--there may be some ingenious way that just hasn't occurred to me. --efn |
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