|
|
Subject:
Best fit equation of a curve on a log log graph
Category: Science > Math Asked by: tmall-ga List Price: $50.00 |
Posted:
16 Sep 2004 12:28 PDT
Expires: 16 Oct 2004 12:28 PDT Question ID: 402159 |
I'm looking for the equation that fits the data listed below. What is the equation that best fits this data? y=f(x)?? On log log paper, the curve appears like the equation 1-e^(-ax) appears on linear linear paper. x y 0.0012 0.002 0.0014 0.022 0.0016 0.044 0.002 0.089 0.003 0.2 0.004 0.31 0.006 0.44 0.008 0.54 0.01 0.61 0.02 0.84 0.04 0.93 0.1 1 1 1 The equation must converge to 1 for large x values. |
|
Subject:
Re: Best fit equation of a curve on a log log graph
Answered By: palitoy-ga on 17 Sep 2004 06:59 PDT Rated: |
Hello Tmall I have used the excellent Curve Expert to compile this list of possible solutions to your data points listed above. This software can be downloaded from http://www.ebicom.net/~dhyams/cvxpt.htm and will draw graphs of each of the possible solutions for you. I would highly recommend at least taking a look at this piece of software (if not purchasing it). An alternative way to look at the data would be to use the zunzun.com website although this is considerably more complicated to use. According to the Curve Expert software the best fit lines for your data are (further statistics are available by using the software): 1) Weibull Model: y=a-b*exp(-c*x^d) a = 0.99494109 b = 1.304623 c = 36.304995 d = 0.73432375 Standard Error: 0.0122013 Correlation Coefficient: 0.9996236 Comments: The fit converged to a tolerance of 1e-006 in 8 iterations. No weighting used. 2) MMF Model: y=(a*b+c*x^d)/(b+x^d) a = -0.10882534 b = 0.0010501178 c = 1.0145978 d = 1.3492462 Standard Error: 0.0123243 Correlation Coefficient: 0.9996159 Comments: The iteration count of 100 was exceeded. The fit failed to converge to tolerance of 0.000001 (CHI2 at 0.001367). No weighting used. 3) Vapor Pressure Model: y=exp(a+b/x+cln(x)) a = 0.011797156 b = -0.0053048177 c = -0.014056123 Standard Error: 0.0154654 Correlation Coefficient: 0.9993279 Comments: The fit converged to a tolerance of 1e-006 in 3 iterations. No weighting used. 4) Modified Hoerl Model: y=a*b^(1/x)*x^c a = 1.0118677 b = 0.99470924 c = -0.014055661 Standard Error: 0.0154654 Correlation Coefficient: 0.9993279 Comments: The fit converged to a tolerance of 1e-006 in 3 iterations. No weighting used. 5) Rational Function: y=(a+bx)/(1+cx+dx^2) a = -0.25241261 b = 194.96896 c = 176.8517 d = 17.203241 Standard Error: 0.0171513 Correlation Coefficient: 0.9992561 Comments: The fit converged to a tolerance of 1e-006 in 8 iterations. No weighting used. 6) Modified Exponential: y=a*e^(b/x) a = 1.0375904 b = -0.005013615 Standard Error: 0.0181261 Correlation Coefficient: 0.9989843 Comments: The fit converged to a tolerance of 1e-006 in 3 iterations. No weighting used. 7) Root Fit: y=a*b^(1/x) a = 1.0375904 b = 0.99499893 Standard Error: 0.0181261 Correlation Coefficient: 0.9989843 Comments: The fit converged to a tolerance of 1e-006 in 3 iterations. No weighting used. 8) Exponential Association (3): y=a(b-exp(-cx)) a = 1.1097553 b = 0.87861712 c = 116.13166 Standard Error: 0.0227064 Correlation Coefficient: 0.9985507 Comments: The fit converged to a tolerance of 1e-006 in 6 iterations. No weighting used. All of these models give excellent correlation coefficients and small standard errors. Perhaps the 'simplest' of these possible solutions is the root fit (#7). If you require any further information please ask for clarification and I will do my best to help. |
tmall-ga
rated this answer:
Exactly what I was looking for and in a very timely manner. Thanks |
|
There are no comments at this time. |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |